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Roller Coaster Problem with KE and PE

  1. Apr 9, 2013 #1
    1. The problem statement, all variables and given/known data

    https://dl.dropbox.com/u/92857534/physicsproblem.png [Broken]

    Note: Solving for part D and E


    2. Relevant equations

    Unsure. Language in the problem seems ambiguous.
    Perhaps (KE + PE)b = (KE + PE)a

    3. The attempt at a solution

    So I think it's done this way.

    From A to B and B to C, the equation would look this way:
    PEb + KEb = KEa + PEa
    PEa = 0, move KEb to right side, left with:
    PEb = KEa - KEb
    so WGH = 1/2mv'^2 - 1/2mv^2

    Am I going the right way about this? If so, where do I go from here when I don't know both velocities?



    Also, for parts A, B, and C, it's simply W = mgΔh, correct? I'm not used to things being easy :P
     
    Last edited by a moderator: May 6, 2017
  2. jcsd
  3. Apr 9, 2013 #2

    mukundpa

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    Homework Helper

    Work energy rule says that the increase in kinetic energy of a body is equal to work done on it.
     
  4. Apr 9, 2013 #3
    Do you think you could be a little less cryptic?
     
  5. Apr 9, 2013 #4

    mukundpa

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    Homework Helper

    Work done by gravity is equal to the increase in kinetic energy of the car. The same is the loss in potential energy. W = mgΔh is correct.
    In second part I think potential energy is to be calculated at different points.
     
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