Rolling motion of a rigid body problem

Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
2 replies · 4K views
Minchi
Messages
2
Reaction score
0
1. A solid sphere has a radius of 0.200 m and a mass of 150 kg. How much work is required to get the sphere rolling with an angular speed of 50.0 rad/s on a horizontal surface? Assume the sphere starts from rest and rolls without slipping

2. The attempt at a solution

I found V first.

V= rw
= 0.2 x 50
=10 m/s

Then Fc

Fc = mv^2/r
= (150)(10)^2 / 0.2
=75000 N

W= F X R
= 75000 x 0.2
= 15000 J

The answer the teacher gave was 1.05 x 10^4 J or 10500 J...

What did I do wrong?

Thank you for your help!
 
Physics news on Phys.org
Minchi said:
1. A solid sphere has a radius of 0.200 m and a mass of 150 kg. How much work is required to get the sphere rolling with an angular speed of 50.0 rad/s on a horizontal surface? Assume the sphere starts from rest and rolls without slipping

2. The attempt at a solution

I found V first.

V= rw
= 0.2 x 50
=10 m/s

Then Fc

Fc = mv^2/r
= (150)(10)^2 / 0.2
=75000 N

W= F X R
= 75000 x 0.2
= 15000 J
This is the rotational energy. In addition to just spinning in place the sphere is moving forward. You have to take the translational kinetic energy into account too.

The answer the teacher gave was 1.05 x 10^4 J or 10500 J...

What did I do wrong?

Thank you for your help!
 
I = mi ri^2
=(150)(0.2)^2
= 6 kg m2

KE= 1/2 I w^2
=(0.5)(6)(50)^2
=7500 J

um...where do I fit this into what I did above?

Was all my steps above required to the question?