Rolling motion of a rigid body problem

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SUMMARY

The problem involves calculating the work required to roll a solid sphere with a radius of 0.200 m and a mass of 150 kg to an angular speed of 50.0 rad/s. The initial calculations incorrectly focused solely on the force and work done due to translational motion, yielding 15,000 J. However, the correct approach requires incorporating both translational and rotational kinetic energy, leading to a total work of 10,500 J as confirmed by the teacher. The moment of inertia for the sphere was calculated as 6 kg·m², which is essential for determining the rotational kinetic energy.

PREREQUISITES
  • Understanding of rotational dynamics and moment of inertia
  • Familiarity with kinetic energy equations for both translational and rotational motion
  • Knowledge of angular velocity and its relationship to linear velocity
  • Basic algebra for manipulating equations and solving for unknowns
NEXT STEPS
  • Study the derivation of the moment of inertia for different shapes, focusing on solid spheres
  • Learn about the conservation of energy in rolling motion scenarios
  • Explore the relationship between angular velocity and linear velocity in rolling objects
  • Investigate the principles of work-energy theorem in both translational and rotational contexts
USEFUL FOR

Students studying physics, particularly those focusing on mechanics, as well as educators looking to clarify concepts related to rotational motion and energy calculations.

Minchi
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1. A solid sphere has a radius of 0.200 m and a mass of 150 kg. How much work is required to get the sphere rolling with an angular speed of 50.0 rad/s on a horizontal surface? Assume the sphere starts from rest and rolls without slipping

2. The attempt at a solution

I found V first.

V= rw
= 0.2 x 50
=10 m/s

Then Fc

Fc = mv^2/r
= (150)(10)^2 / 0.2
=75000 N

W= F X R
= 75000 x 0.2
= 15000 J

The answer the teacher gave was 1.05 x 10^4 J or 10500 J...

What did I do wrong?

Thank you for your help!
 
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Minchi said:
1. A solid sphere has a radius of 0.200 m and a mass of 150 kg. How much work is required to get the sphere rolling with an angular speed of 50.0 rad/s on a horizontal surface? Assume the sphere starts from rest and rolls without slipping

2. The attempt at a solution

I found V first.

V= rw
= 0.2 x 50
=10 m/s

Then Fc

Fc = mv^2/r
= (150)(10)^2 / 0.2
=75000 N

W= F X R
= 75000 x 0.2
= 15000 J
This is the rotational energy. In addition to just spinning in place the sphere is moving forward. You have to take the translational kinetic energy into account too.

The answer the teacher gave was 1.05 x 10^4 J or 10500 J...

What did I do wrong?

Thank you for your help!
 
I = mi ri^2
=(150)(0.2)^2
= 6 kg m2

KE= 1/2 I w^2
=(0.5)(6)(50)^2
=7500 J

um...where do I fit this into what I did above?

Was all my steps above required to the question?
 

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