Rotating coordinate system, velocity

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The discussion focuses on finding the velocity v0 in a rotating coordinate system where the angular velocity is defined as ω = tk. The position vector in the rotating frame is given by r0(t) = (t + 1)i0 + t^2j0. Participants emphasize that simply differentiating r0 is insufficient; one must also account for the time-dependent nature of the unit vectors in the rotating frame. The need to differentiate these unit vectors is highlighted as critical for accurately determining v0. The conversation underscores the complexities involved in working with rotating reference frames in physics.
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Homework Statement



Two coordinate systems xyz (…fixed) and x0y0z0 (moving) coincide at time t = 0.
The moving system is rotating about the …fixed z axis, which coincides with z0 axis. The angular velocity is given by ω = tk = tk0. The position vector as measured in the rotational frame is equal to
r0 (t) = (t + 1) i0 + t^2 j0:
1. Using the rotating frame …find v0.

Homework Equations



ω = tk = tk0
r0 (t) = (t + 1) i0 + t^2 j0

The Attempt at a Solution



So i know to find v0, i cannot just differentiate r0. but i am stuck.
 
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Welcome to PF;
v0 is the velocity in the rotating reference frame?
r0 is the position in the rotating frame wrt time?

You also need to differentiate the unit vectors.
See: http://home.comcast.net/~szemengtan/ClassicalMechanics/SingleParticle.pdf
section 1.8 (p15)
 
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