Rotation of Axes: 5x^3+10x^2+20x+15

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Homework Help Overview

The problem involves the rotation of the polynomial equation 5x^3 + 10x^2 + 20x + 15 through an angle of 45 degrees to find the corresponding equation in a new xy coordinate system.

Discussion Character

  • Exploratory, Problem interpretation, Assumption checking

Approaches and Questions Raised

  • Participants discuss the transformation equations for the new coordinates and express uncertainty about how to derive the new equation from these transformations. There is a suggestion to substitute the original polynomial into the new coordinate expressions to explore the relationship between X and Y.

Discussion Status

The discussion is ongoing, with participants exploring different approaches to express the rotated equation. Some have provided equations for the transformation, while others are questioning how to proceed with substituting the original polynomial into these new coordinates.

Contextual Notes

Participants are navigating the challenge of deriving a new equation from the transformed coordinates, indicating a potential gap in understanding how to eliminate the parameter x for a final expression.

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Homework Statement



5x^3+10x^2+20x+15 is rotated through the angle 45 degrees to new xy coordinate system.Whats the equation to the coordinate system?

Homework Equations





The Attempt at a Solution


New X= xcos(theta)+ycos(theta) New Y=-xsin(theta)+ycos(theta)
 
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Ledsnyder said:

Homework Statement



5x^3+10x^2+20x+15 is rotated through the angle 45 degrees to new xy coordinate system.Whats the equation to the coordinate system?

Homework Equations





The Attempt at a Solution


New X= xcos(theta)+ycos(theta) New Y=-xsin(theta)+ycos(theta)

So...? Show the rest of your work.
 
I have the equations.I just don't know how to find the new equation based on the coordinates.
 
Ledsnyder said:
I have the equations.I just don't know how to find the new equation based on the coordinates.

What is preventing you from putting in ##y = 5x^3+10x^2+20x+15## into the expressions for ##X## and ##Y##? This will, at least, give you a "parametric" form of the relationship between ##X## and ##Y## along the curve (the parameter will be ##x##). It might be harder if you want an explicit formula of the form ##Y = f(X)## (or maybe ##G(X,Y) = 0##) in which the parameter ##x## has been eliminated, but I suggest you give it a try. Or have you already done that?
 

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