Rotational Acceleration of an Amusement Park Carousel

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Homework Help Overview

The problem involves calculating the rotational acceleration of an amusement park carousel that takes a specific time to complete a revolution and then slows down over a certain number of revolutions. The context is within the subject area of rotational motion and dynamics.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the initial angular velocity and the conditions for stopping the carousel, with some attempting to apply the rotational kinematics equation. There are questions about the correctness of the calculated angular acceleration values and the factors involved in the calculations.

Discussion Status

The discussion is ongoing, with participants providing different angular acceleration values and questioning the initial assumptions regarding angular velocity. There is an acknowledgment of a potential oversight in calculations, but no consensus has been reached on the correct approach or final answer.

Contextual Notes

Participants are working under the constraints of the problem statement, including the maximum speed of the carousel and the specifics of the slowing down process. There is also a mention of a separate problem regarding the acceleration of an ice cube in a hemispherical bowl, indicating a broader context of physics discussions.

kolua
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Homework Statement


Moving at its maximum safe speed, an amusement park carousel takes 12 s to complete a revolution. At the end of the ride, it slows down smoothly, taking 3.5rev to come to a stop. What is the magnitude of the rotational acceleration of the carousel while it is slowing down?

Homework Equations


w2=wo2+2alpha theta

The Attempt at a Solution


plug in and get -pi/144 rad/s2 is this right?
 
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or -pi2/504 s-2
 
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Likes   Reactions: Daeho Ro
When it moves with maximum speed, the angular velocity is ## \omega_i = \pi / 12. ## You want to stop it within ## 3.5 ## revolution, that is ## \theta_f - \theta_i = 7\pi ## and it have to be ## \omega_f = 0. ## Then, you can get the angular acceleration, ## \alpha. ##
 
Daeho Ro said:
When it moves with maximum speed, the angular velocity is ## \omega_i = \pi / 12. ## You want to stop it within ## 3.5 ## revolution, that is ## \theta_f - \theta_i = 7\pi ## and it have to be ## \omega_f = 0. ## Then, you can get the angular acceleration, ## \alpha. ##
shouldn't the angular velocity be pi/6?
 
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Likes   Reactions: Daeho Ro
Oh, yes I missed the factor ## 2##.
 
Daeho Ro said:
Oh, yes I missed the factor ## 2##.
Can you also help me check this one? You hold a small ice cube near the top edge of a hemispherical bowl of radius 100 mm. You release the cube from rest. What is the magnitude of its acceleration at the instant it reaches the bottom of the bowl? Ignore friction. is a=2g=19.6 m/s2
 
kolua said:
or -pi2/504 s-2
Which one?

Always show your work in detail.
 

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