Rotational Energy, finding speed of rotation. Simple Problem.

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The discussion focuses on a physics problem involving a pole colliding with a mass and the subsequent rotation of the pole. The initial kinetic energy of the pole is calculated, but the conservation of energy is deemed inappropriate for this inelastic collision where the mass sticks to the pole. Instead, the conservation of momentum should be applied to find the angular velocity after the collision. A suggestion is made to analyze the problem from the center of mass frame to simplify calculations. The key takeaway is that momentum is conserved in collisions, even when kinetic energy is not.
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Homework Statement



A pole P (300kg, length = 12m) is sliding on a frictionless surface at 8.28m/s. The pole's velocity is perpendicular to the poles length. A mass N (.5kg) collides with one end of the pole at 1043m/s and sticks.

How fast does the pole rotate after the collision?

Homework Equations



I'm assuming conservation of energy.

Kinetic energy: .5 x M x V2

Rotational Energy: .5 x I x w2

Where I = moment of inertia = 1/12M x L2 (radius was not given in the problem, I'm assuming the moment of inertia for a thin rod)

w = angular speed of rotation

The Attempt at a Solution



Pole's kinetic energy before impact:

.5 x 300kg x 8.28m/s2

Pole's kinetic + rotational energy after impact:

.5 x 300.5kg x v2 + .5 x 1/12*(300.5kg x (12m)2)w2

Due to the conservation of energy:

.5 x 300kg x 8.28m/s2 = .5 x 300.5kg x v2 + .5 x 1/12*(300.5kg x (12m)2)w2I'm assuming the pole's center of mass is not significantly changed after the collision.

I also know that w(angular speed) = VCenter Mass/R

However, using this strategy, I result with two unknowns within my equation.

Any help with this is greatly appreciated.
 
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This is a collision. Energy is sometimes conserved in a collision but not when the masses stick together. What quantity other than energy is conserved in a collision, even when the masses stick together?

Are you sure the initial speed of the mass is 1043 m/s? It sounds awfully large.
 
As kuruman said, assuming conservation of energy is incorrect. In fact, in such collisions where the two bodies stick together, so-called 'plastic' collisions, mechanical energy is never conserved (You can prove this by considering a plastic collision between two masses, m1 and m2, in their center of mass system. The total momentum is 0 in this particular system, and yet you have kinetic energy prior to the collision, and none afterwards!)

As for this problem, my suggestion is for you to try and solve it from the system moving along with the pole if you don't succeed in solving from the laboratory system. Things may prove a bit more simple.
In fact, since the question only asks you for the angular velocity of the rod+mass after the collision, solving from the center of mass system is even preferable.

Like kuruman asked, what quantity is always conserved in collisions, even when they're plastic?
 
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The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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