Rotational Energy, finding speed of rotation. Simple Problem.

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SUMMARY

The discussion centers on calculating the angular speed of a pole after a collision with a mass, utilizing principles of rotational energy and momentum conservation. The pole, weighing 300 kg and measuring 12 m in length, slides at 8.28 m/s before being struck by a 0.5 kg mass traveling at 1043 m/s. Participants clarify that mechanical energy is not conserved in plastic collisions, emphasizing the importance of momentum conservation instead. The recommended approach is to analyze the problem from the center of mass frame to simplify calculations.

PREREQUISITES
  • Understanding of kinetic energy and rotational energy equations.
  • Knowledge of conservation of momentum principles in collisions.
  • Familiarity with moment of inertia calculations for rigid bodies.
  • Ability to analyze problems from different reference frames, such as the center of mass frame.
NEXT STEPS
  • Study the concept of plastic collisions and their impact on energy conservation.
  • Learn how to calculate moment of inertia for various shapes, including rods and disks.
  • Explore the center of mass frame and its applications in collision problems.
  • Review angular velocity calculations and their relationship to linear velocity in rotating systems.
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Physics students, educators, and anyone interested in understanding the dynamics of collisions and rotational motion in mechanics.

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Homework Statement



A pole P (300kg, length = 12m) is sliding on a frictionless surface at 8.28m/s. The pole's velocity is perpendicular to the poles length. A mass N (.5kg) collides with one end of the pole at 1043m/s and sticks.

How fast does the pole rotate after the collision?

Homework Equations



I'm assuming conservation of energy.

Kinetic energy: .5 x M x V2

Rotational Energy: .5 x I x w2

Where I = moment of inertia = 1/12M x L2 (radius was not given in the problem, I'm assuming the moment of inertia for a thin rod)

w = angular speed of rotation

The Attempt at a Solution



Pole's kinetic energy before impact:

.5 x 300kg x 8.28m/s2

Pole's kinetic + rotational energy after impact:

.5 x 300.5kg x v2 + .5 x 1/12*(300.5kg x (12m)2)w2

Due to the conservation of energy:

.5 x 300kg x 8.28m/s2 = .5 x 300.5kg x v2 + .5 x 1/12*(300.5kg x (12m)2)w2I'm assuming the pole's center of mass is not significantly changed after the collision.

I also know that w(angular speed) = VCenter Mass/R

However, using this strategy, I result with two unknowns within my equation.

Any help with this is greatly appreciated.
 
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This is a collision. Energy is sometimes conserved in a collision but not when the masses stick together. What quantity other than energy is conserved in a collision, even when the masses stick together?

Are you sure the initial speed of the mass is 1043 m/s? It sounds awfully large.
 
As kuruman said, assuming conservation of energy is incorrect. In fact, in such collisions where the two bodies stick together, so-called 'plastic' collisions, mechanical energy is never conserved (You can prove this by considering a plastic collision between two masses, m1 and m2, in their center of mass system. The total momentum is 0 in this particular system, and yet you have kinetic energy prior to the collision, and none afterwards!)

As for this problem, my suggestion is for you to try and solve it from the system moving along with the pole if you don't succeed in solving from the laboratory system. Things may prove a bit more simple.
In fact, since the question only asks you for the angular velocity of the rod+mass after the collision, solving from the center of mass system is even preferable.

Like kuruman asked, what quantity is always conserved in collisions, even when they're plastic?
 
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