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A potter's wheel having a radius of 0.50 m and a moment of inertia of 12 kg m^2 is rotating freely at 50 rev/min. The potter can stop the wheel in 6.0 sec by pressing a wet rag against the rim and exerting a radially inward force of 70 N. Find the effective coefficient of kinetic friction between the wheel and the rag.

What I know:

I know with the info given, I must use the angular version of newton's 2nd law.

Sum (Torque) = I(Moment of Inertia) Alpha (Angular Acceleration).

But I am unsure how this even relates to the coeff. of kinetic friction.

Any help???

Thanks In Advance

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# Homework Help: Rotational Equilibrium and Rotational Dynamics problem

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