Rotational Form of Newton's Second Law - Help

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SUMMARY

The discussion focuses on calculating the torque required for a turntable to reach an angular speed of 3.49 rad/s in 2 revolutions, starting from rest. The turntable is modeled as a uniform disk with a diameter of 0.305m and a mass of 0.22kg. The moment of inertia (I) is calculated using the formula I = 0.5MR², resulting in 2.56x10^-3 kgm². The correct conversion of angular speed from revolutions per second to radians per second is emphasized, clarifying that 3.49 rev/s is equivalent to 3.49 rad/s.

PREREQUISITES
  • Understanding of rotational dynamics and torque
  • Familiarity with the moment of inertia formula I = 0.5MR²
  • Knowledge of angular acceleration and its calculation using α = (ωf - ωi)/t
  • Ability to convert between different units of angular speed
NEXT STEPS
  • Study the kinematic equations for rotational motion
  • Learn how to derive torque using τ = αI
  • Explore the relationship between angular displacement (θ) and revolutions
  • Review additional equations for rotational motion in physics textbooks
USEFUL FOR

Students studying physics, particularly those focusing on rotational dynamics, as well as educators seeking to clarify concepts related to torque and angular motion.

Quarkn
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Homework Statement



A turntable must spin at 33.3RPM (3.49 rev/s) to play an old fashioned vinyl record. How much torque must the motor deliver if the turntable is to reach its final angular speed in 2 revolutions, starting from rest? The turntable is a uniform disk of diameter .305m and mass 0.22kg.


Homework Equations



I = 0.5MR²
\tau = \alphaI
\alpha = (ωf-ωi)/t

The Attempt at a Solution



I=(0.5)(0.22kg)(.1525²)=2.56x10^-3 kgm²
 
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Quarkn said:

Homework Statement



A turntable must spin at 33.3RPM (3.49 rev/s)...
There's a little problem with your conversion of units for ω. Instead of "rev/s", it should be 3.49 ___/s (?)
...to play an old fashioned vinyl record. How much torque must the motor deliver if the turntable is to reach its final angular speed in 2 revolutions, starting from rest? The turntable is a uniform disk of diameter .305m and mass 0.22kg.


Homework Equations



I = 0.5MR²
\tau = \alphaI
\alpha = (ωf-ωi)/t

The Attempt at a Solution



I=(0.5)(0.22kg)(.1525²)=2.56x10^-3 kgm²
Yup, that's I.

Your book should have even more relevant equations for rotational motion. You want one that involves θ, so that you can use the information that it takes 2 revolutions to get the turntable up to speed. You can check in your textbook for the full list of equations.
 
Starting from rest at a point O, let's call it, the motor supplies a torque so that by the second time we pass O, the angular speed is 3.49 rev/s. Based on this, you can use one of the kinematics equations (re-vamped into their respective rotational forms) and then incorporate the mass of the disc to find the torque.
 
Redbelly98 said:
There's a little problem with your conversion of units for ω. Instead of "rev/s", it should be 3.49 ___/s (?)

Yup, that's I.

Your book should have even more relevant equations for rotational motion. You want one that involves θ, so that you can use the information that it takes 2 revolutions to get the turntable up to speed. You can check in your textbook for the full list of equations.

Yes, it is 3.49 rad/s, sorry :P

Anyways, I found out the answer. My problem was that I didn't know theta was used as the 2 revolutions.
 
Okay, glad it worked out.
 

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