Rolling Objects, Friction, and Newton's Second Law

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SUMMARY

The discussion focuses on the application of Newton's Second Law in rotational dynamics, specifically regarding a ring rolling down an incline and the behavior of a yoyo when a vertical force is applied. The equations of motion, Ʃτ=Iα and ƩF=ma, are correctly applied to analyze the ring's acceleration, revealing that at θ=0, static friction is zero, allowing the ring to maintain uniform velocity. The yoyo's behavior is explained through torque, clarifying that it does not move horizontally when pulled vertically but can rise and rotate due to the applied force.

PREREQUISITES
  • Understanding of Newton's Second Law
  • Familiarity with rotational dynamics concepts
  • Knowledge of torque and its effects on motion
  • Basic principles of static and kinetic friction
NEXT STEPS
  • Study the implications of static friction in rotational motion
  • Explore the relationship between torque and angular acceleration
  • Investigate the dynamics of rolling objects on inclined planes
  • Learn about the effects of forces on yoyo motion and rotation
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Physics students, educators, and anyone interested in understanding the principles of rotational dynamics and the application of Newton's laws in real-world scenarios.

Starwing123
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Homework Statement


In rotational dynamics, a typical problem would be along the lines of a ring with mass m and radius r rolling down a hill with angle θ to the horizontal. Find the acceleration of the ring.



Homework Equations


Ʃτ=I\alpha = r x (friction)
ƩF = ma = mgsinθ - (friction)

The Attempt at a Solution


These equations usually give the correct answer for the problem (plug in the numbers, isolate, solve for whatever the question asks). My question is that these equations don't seem to make sense if θ=0. That would imply that F = -(friction) and the ring is slowing down (if it was moving originally). However, that is not the case if there is no rolling friction. Why does this equation break down?

A similar dilemma I have is given a yoyo on the floor, if you pull vertically up on the string, the yoyo rolls in a certain direction. However, there is no net force horizontally, so how does it roll? If the answer is that the torque causes it, when why would Newton's second law even apply in the case of yoyos rolling down a string in midair?
 
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Starwing123 said:

Homework Statement


In rotational dynamics, a typical problem would be along the lines of a ring with mass m and radius r rolling down a hill with angle θ to the horizontal. Find the acceleration of the ring.



Homework Equations


Ʃτ=I\alpha = r x (friction)
ƩF = ma = mgsinθ - (friction)

The Attempt at a Solution


These equations usually give the correct answer for the problem (plug in the numbers, isolate, solve for whatever the question asks). My question is that these equations don't seem to make sense if θ=0. That would imply that F = -(friction) and the ring is slowing down (if it was moving originally). However, that is not the case if there is no rolling friction. Why does this equation break down?

It does not break down. It simply means that the static friction is zero and the ring rolls with uniform velocity. You know that static friction is not a defined force, you only know its maximum possible value.

Starwing123 said:
A similar dilemma I have is given a yoyo on the floor, if you pull vertically up on the string, the yoyo rolls in a certain direction. However, there is no net force horizontally, so how does it roll? If the answer is that the torque causes it, when why would Newton's second law even apply in the case of yoyos rolling down a string in midair?

The yoyo will not start to move horizontally if you pull the string exactly vertical. But it will rise a bit, detached from ground and starting to rotate...


ehild
 

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