Rotational Inertia with varying axis of rotation?

[Javasauce]

Homework Statement

Four identical particles of mass 0.475 kg each are placed at the vertices of a 1.73 m x 1.73 m square and held there by four massless rods, which form the sides of the square. What is the rotational inertia of this rigid body about an axis that (a) passes through the midpoints of opposite sides and lies in the plane of the square, (b) passes through the midpoint of one of the sides and is perpendicular to the plane of the square, and (c) lies in the plane of the square and passes through two diagonally opposite particles?

Homework Equations

I_com = (1/12)M(a^2 + b^2)

The Attempt at a Solution

M = 0.475 * 4 = 1.9kg
I = (1/12)M(a^2 + b^2) = (1/12)(1.9)(1.73^2 * 2) = 0.948 kg*m^2

I believe this answer would be correct for part (a), but how do I go about calculating the rotational inertia for the other two locations of the rotational axis? Any help would be greatly appreciated, thanks!

 

[Javasauce]

bump, can anyone lend any advice to this question? :-\