Squeezebox
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θ=ω_0 t+1/2 αt^2 then n=theta/2pi
θ=0.5*pi*0.2+.5*1.8*pi*.04=pi(0.1+0.036)=0.136*pi
θ/2*pi=0.136*pi/2*pi=0.136/2=0.068 rev
θ=0.5*pi*0.2+.5*1.8*pi*.04=pi(0.1+0.036)=0.136*pi
θ/2*pi=0.136*pi/2*pi=0.136/2=0.068 rev