Rotational kinetic energy of two astronauts connected by a rope

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URGENT: rotatonal KE

Two astronauts each having a mass of 54 kg are connected by a 10 m rope of negligible mass. They are isolated in space, orbiting about their centre of mass at speeds of 3.7 m/s. Calculate the rotational energy of the two astronauts.

A. 739.3 J
B. 1478.5 J
C. 29.6 J
D. 317.9 J
E. 369.6 J

Which one is it?

I did:

KE= 1/2 (I + I) omega ^2

and it turned out to be A. Is it correct?
 
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