Rotational Motion of a cylinder

  • Thread starter Carpe Mori
  • Start date
  • #1
19
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Homework Statement


A hollow cylinder (hoops) is rolling on a horizontal surface at speed v = 4.3 m/s when it reaches a 15 degree incline (a) how far up the incline will it go? (b) how long will it be on the incline before it arrives back at the bottom?


Homework Equations



PE = KE + RE
SOH CAH TOA

w = v/r

I = mr^2


The Attempt at a Solution



A) I figured out letter A with conservation of Energy (yawn) distance = 7.3 m

B)I am not sure exactly how to solve this problem. If it was a non rotating cube i could do it very easilly =D. I am sure the fact that it is rotating though affects it somehow. For a cube I would use the Kinetics equations (y = -.5gt^2 + vt + y0) to solve for time. Could someone help me out thanks =D
 

Answers and Replies

  • #2
335
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the time taken to go up the incline=the time taken to come down.
calculate time taken to go up sing simple kinamtic relations and then double it to get the desired result.

use velocity final=0
velocity[initial]=4.3 m/s
distance=7.3 m

now the important part is accln- i leave it to you to figure it out.
use =s=ut+1/2at^2
 

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