Rotational Motion of a Hanging Mass

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SUMMARY

The discussion focuses on the rotational motion of a hanging mass, specifically a ball of mass m attached to a string of length l. The problem involves calculating the angular velocity (w) as a function of the angle (θ) using conservation of energy principles. The correct formula for angular velocity derived from the conservation of energy is w = sqrt(2g/l*(cos(θ) - cos(θi))). Additionally, the angular momentum (|L|) is expressed as |L| = ml²w, and the relationship t = dL/dt is established through differentiation.

PREREQUISITES
  • Understanding of conservation of energy principles in physics
  • Familiarity with angular velocity and angular momentum concepts
  • Knowledge of gravitational potential energy and kinetic energy equations
  • Basic calculus for differentiation and understanding of time derivatives
NEXT STEPS
  • Study the derivation of angular velocity in rotational dynamics
  • Learn about the conservation of mechanical energy in different systems
  • Explore the relationship between angular momentum and torque
  • Investigate the applications of rotational motion in real-world scenarios
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Students studying physics, particularly those focusing on mechanics, as well as educators and anyone interested in understanding the principles of rotational motion and energy conservation.

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Homework Statement


Consider a ball of mass m on the end of a string of length l. It hangs from a frictionless pivot. The ball is pulled out so that the string makes an angle thetai with the vertical and is then released.
a. Find w (angular velocity) as a function of the angle the strings makes with the vertical. (Hint: Use conservation of energy.)
b. Find the angular momentum of the ball using |L| = ml^2w
c. Show that t = dL/dt by differentiating L and finding t from its definition.

Homework Equations


U1 + K1 = U2 + K2
V = rw


The Attempt at a Solution


for a:

The answer, according to the book, is w = sqrt(2g/l*(cos(theta) - cos(thetai)))

I used the conservation of energy and got w = sqrt(2g/l*(1 - cos(thetai))). I'm lost.. I don't know where the book got cos(theta)
 
Physics news on Phys.org
at an angle θi, find the energy at that point.

Now this energy is converted into gravitational pe and ke at an angle θ. Find this energy here.


Equate the two.
 

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