A uniform solid disk of radius 7.1m and mass 30.3kg is free to rotate on a fricionless pivot through a point on its rim. [picture: http://www.wellesley.edu/Physics/phyllisflemingphysics/107_p_angular_images/figure_9.gif] [Broken]
If the disk is released from rest in the position shown, what is the speed of its center of mass when the disk reaches the position indicated by the dashed circle?
What is the speed of the lowest point on the disk in the dashed position?
mgh = 1/2 Iw^2 + 1/2mv^2.
The Attempt at a Solution
From the above equation, I was able to subsitute w = v/r and solved for v...v = (4/3gh)^1/2. I don't know if this velocity pertains to the one about the center of mass or the lowest point. Please help! Thank you!
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