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Rotational Motion (thin hollow pipe)

  1. Nov 16, 2008 #1
    1. The problem statement, all variables and given/known data
    thin, hollow 60.0 g section of pipe of radius 14.0 cm starts rolling (from rest) down a 17.5° incline 5.60 m long.
    (a) If the pipe rolls without slipping, what will be its speed at the base of the incline?
    (b) What will be its total kinetic energy at the base of the incline?
    (c) What minimum value must the coefficient of static friction have if the pipe is not to slip?


    2. Relevant equations



    3. The attempt at a solution
    I got a) V=sqrt(gh) V=4.06m/s and b) KE=mv^2=mgh KE=0.989J which are correct.
    c) I need help with this one, I am not sure where to begin.
     
  2. jcsd
  3. Nov 17, 2008 #2

    Redbelly98

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    This is a tricky question.

    Without thinking this through completely, I'll suggest drawing a force diagram for the piple, including friction. Then some equations involving Newton's 2nd Law, and the torque-rotation version of Newton's 2nd Law.
     
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