Rotational Motion (thin hollow pipe)

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SUMMARY

The discussion focuses on the physics of a thin hollow pipe rolling down a 17.5° incline. The calculated speed at the base of the incline is 4.06 m/s, and the total kinetic energy at that point is 0.989 J. The challenge lies in determining the minimum coefficient of static friction required to prevent slipping, which involves applying Newton's 2nd Law and torque equations. Participants emphasize the importance of drawing a force diagram to visualize the forces acting on the pipe.

PREREQUISITES
  • Understanding of rotational motion and torque
  • Familiarity with Newton's 2nd Law
  • Knowledge of kinetic energy equations
  • Basic principles of friction and rolling motion
NEXT STEPS
  • Study the relationship between torque and angular acceleration
  • Learn about the equations governing rolling motion without slipping
  • Explore static friction coefficients and their calculations
  • Investigate energy conservation principles in rotational dynamics
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Physics students, educators, and anyone interested in understanding the dynamics of rolling objects and the principles of rotational motion.

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Homework Statement


thin, hollow 60.0 g section of pipe of radius 14.0 cm starts rolling (from rest) down a 17.5° incline 5.60 m long.
(a) If the pipe rolls without slipping, what will be its speed at the base of the incline?
(b) What will be its total kinetic energy at the base of the incline?
(c) What minimum value must the coefficient of static friction have if the pipe is not to slip?


Homework Equations





The Attempt at a Solution


I got a) V=sqrt(gh) V=4.06m/s and b) KE=mv^2=mgh KE=0.989J which are correct.
c) I need help with this one, I am not sure where to begin.
 
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This is a tricky question.

Without thinking this through completely, I'll suggest drawing a force diagram for the piple, including friction. Then some equations involving Newton's 2nd Law, and the torque-rotation version of Newton's 2nd Law.
 

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