I Rotational stability and Fosbury Flop questions

  • I
  • Thread starter Thread starter John3022
  • Start date Start date
  • Tags Tags
    Center Gravity
AI Thread Summary
The discussion centers on the physics of stability in high jumping and cycling, particularly the Fosbury flop technique and the dynamics of bicycle stability at higher speeds. It highlights that there is no single equation for bicycle stability; rather, it involves a collection of interrelated equations and parameters. Gyroscopic precession is noted as a key factor, where increased speed reduces the precession rate for a given torque. The conversation also touches on different types of stability, including slow, gradual changes versus rapid, potentially dangerous shifts like a "tank slapper." Overall, understanding these dynamics is crucial for both high jump techniques and bicycle safety at speed.
John3022
Messages
2
Reaction score
0
TL;DR Summary
Why are rotations more stable the faster they rotate and what is the consequence of the fosbury flop?
What is the consequence of the center of gravity passing below the rod in the high jump? Fosbury flop.
Which equation is responsible for a bike being more stable the faster it's driven? and in rotating things in general being more stable the faster they're rotating.
 
Physics news on Phys.org
Welcome, John!

Please, see:
https://www.pbs.org/newshour/science/the-not-so-hidden-physics-of-your-favorite-olympic-event

high-jump-physics-03-1200x675.png
 
John3022 said:
Which equation is responsible for a bike being more stable the faster it's driven? and in rotating things in general being more stable the faster they're rotating.
Bicycles are complicated. There is more than one thing going on. You should not expect to find a single equation with a single unknown called "stability". Instead, you will find a collection of inter-related equations with a plethora of parameters.

Gyroscopic precession in particular is a bit simpler. You are probably concerned with torque-induced precession: https://en.wikipedia.org/wiki/Precession#Classical_(Newtonian)

The faster something is spinning, the less precession rate you get for a fixed input torque.
The faster a bike is moving, the more centripetal force you get for a fixed yaw rate.
 
  • Like
Likes russ_watters
Welcome to PF. :smile:

John3022 said:
Which equation is responsible for a bike being more stable the faster it's driven?
Which kind of stability? Stability when everything is mellow and changing slowly, or the loss of stability called a "tank slapper" at speed? (Full disclosure -- I saved my one and only life threatening tank slapper merging onto a freeway at high speed in an early morning commute, and installed a steering damper on my CBR600F4 the next week).

 
Consider an extremely long and perfectly calibrated scale. A car with a mass of 1000 kg is placed on it, and the scale registers this weight accurately. Now, suppose the car begins to move, reaching very high speeds. Neglecting air resistance and rolling friction, if the car attains, for example, a velocity of 500 km/h, will the scale still indicate a weight corresponding to 1000 kg, or will the measured value decrease as a result of the motion? In a second scenario, imagine a person with a...
Dear all, in an encounter of an infamous claim by Gerlich and Tscheuschner that the Greenhouse effect is inconsistent with the 2nd law of thermodynamics I came to a simple thought experiment which I wanted to share with you to check my understanding and brush up my knowledge. The thought experiment I tried to calculate through is as follows. I have a sphere (1) with radius ##r##, acting like a black body at a temperature of exactly ##T_1 = 500 K##. With Stefan-Boltzmann you can calculate...
Thread 'Griffith, Electrodynamics, 4th Edition, Example 4.8. (First part)'
I am reading the Griffith, Electrodynamics book, 4th edition, Example 4.8 and stuck at some statements. It's little bit confused. > Example 4.8. Suppose the entire region below the plane ##z=0## in Fig. 4.28 is filled with uniform linear dielectric material of susceptibility ##\chi_e##. Calculate the force on a point charge ##q## situated a distance ##d## above the origin. Solution : The surface bound charge on the ##xy## plane is of opposite sign to ##q##, so the force will be...
Back
Top