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Homework Help: Rotational velocity of a system that has a mass launched at it stick to it

  1. Oct 26, 2007 #1
    1. The problem statement, all variables and given/known data
    On a frictionless table, a glob of clay of mass 0.74 kg strikes a bar of mass 1.90 kg perpendicularly at a point 0.48 m from the center of the bar and sticks to it. If the bar is 1.50 m long and the clay is moving at 6.8 m/s before striking the bar, at what angular speed does the bar/clay system rotate about its center of mass after the impact?

    2. Relevant equations
    displacement of center of mass = m1x1 + m2x2 \ m1 + m2
    Ip = Icm + md^2
    mVo = IW

    3. The attempt at a solution

    displacement of center of mass = 1.90*.48 / .74 *.190
    = .6486

    Ip = 1.90(.75^2) + (.74+1.90)(.48)
    = 2.34

    mcVo = IW
    .74(6.8) = 2.34 W
    = 2.15 rad/s
  2. jcsd
  3. Oct 27, 2007 #2

    I think u should check the last equation. Furthermore, please apply conservation of angular momentum carefully.
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