1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Rotational velocity of a system that has a mass launched at it stick to it

  1. Oct 26, 2007 #1
    1. The problem statement, all variables and given/known data
    On a frictionless table, a glob of clay of mass 0.74 kg strikes a bar of mass 1.90 kg perpendicularly at a point 0.48 m from the center of the bar and sticks to it. If the bar is 1.50 m long and the clay is moving at 6.8 m/s before striking the bar, at what angular speed does the bar/clay system rotate about its center of mass after the impact?


    2. Relevant equations
    displacement of center of mass = m1x1 + m2x2 \ m1 + m2
    Ip = Icm + md^2
    mVo = IW


    3. The attempt at a solution

    displacement of center of mass = 1.90*.48 / .74 *.190
    = .6486

    Ip = 1.90(.75^2) + (.74+1.90)(.48)
    = 2.34

    mcVo = IW
    .74(6.8) = 2.34 W
    = 2.15 rad/s
     
  2. jcsd
  3. Oct 27, 2007 #2

    I think u should check the last equation. Furthermore, please apply conservation of angular momentum carefully.
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?



Similar Discussions: Rotational velocity of a system that has a mass launched at it stick to it
Loading...