On a frictionless table, a glob of clay of mass 0.240kg strikes a bar of mass 1.560kg perpendicularly at a point 0.390m from the center of the bar and sticks to it.
a) If the bar is 1.260m long and the clay is moving at 9.300m/s before striking the bar, what is the final speed of the center of mass?
b) At what angular speed does the bar/clay system rotate about its center off mass after the impact (in rad/s)?
The Attempt at a Solution
I have found a) which is 1.24m/s.
In the case of b), I'm not sure on where to start. I have calculated that the center of mass is 0.682. I'm not sure on how to continue by using conservation of angular momentum, because we will have:
Icwc + Irwr = Ifwf
I'm not sure on how to continue. Isn't it possible to solve this problem by taking as a reference the center of the rod? (angular momentum will be conserved or not?)