Row Reduction Question: Independent w1 or w2? Answer Revealed!

  • Thread starter Thread starter transgalactic
  • Start date Start date
  • Tags Tags
    Reduction Row
Click For Summary
SUMMARY

The discussion centers on the linear independence of vectors w1 and w2 with respect to the vector group defined by v1, v2, and v3. It is established that w2 is independent of the span of v1, v2, and v3, while w1 is not. The vectors are defined as follows: v1 = [1, 1, -2, 1], v2 = [3, 0, 4, -1], v3 = [-1, 2, 5, 2], w1 = [8, -10, 18, -14], and w2 = [3, 4, 1, 1]. The key to determining independence lies in checking if w1 and w2 can be expressed as linear combinations of v1, v2, and v3.

PREREQUISITES
  • Understanding of linear algebra concepts, specifically linear independence and span.
  • Familiarity with vector representation in R^n.
  • Ability to solve systems of linear equations.
  • Knowledge of matrix operations and their applications in determining vector relationships.
NEXT STEPS
  • Learn how to determine the span of a set of vectors using Gaussian elimination.
  • Study the concept of linear combinations and their role in vector spaces.
  • Explore the use of the Rank-Nullity Theorem in linear algebra.
  • Investigate the implications of vector independence in higher-dimensional spaces.
USEFUL FOR

Students and professionals in mathematics, particularly those studying linear algebra, as well as educators looking for clear examples of vector independence and span in practical applications.

transgalactic
Messages
1,386
Reaction score
0
which one of w1 or w2 linear independent of the v groupr??
i got to the situation that each one of them could be independent and the other not
??
the answer in the book is that w2 is independent and the other is not
[tex] v_1=\begin{bmatrix}<br /> 1\\ <br /> 1\\ <br /> -2\\ <br /> 1<br /> \end{bmatrix}<br /> v_2=\begin{bmatrix}<br /> 3\\ <br /> 0\\ <br /> 4\\ <br /> -1<br /> \end{bmatrix}<br /> v_3=\begin{bmatrix}<br /> -1\\ <br /> 2\\ <br /> 5\\ <br /> 2<br /> \end{bmatrix}<br /> w_1=\begin{bmatrix}<br /> 8\\ <br /> -10\\ <br /> 18\\ <br /> -14<br /> \end{bmatrix}<br /> w_2=\begin{bmatrix}<br /> 3\\ <br /> 4\\ <br /> 1\\ <br /> 1<br /> \end{bmatrix}[/tex]
http://img147.imageshack.us/img147/8002/64728417.th.gif
 
Last edited by a moderator:
Physics news on Phys.org
did solved it correctly?
 
You shouldn't need to ask whether you solved it correctly, since it's easy enough to check.

Your problem boils down to two questions:
  1. Does w1 belong to the span of v1, v2, and v3? In other words, are there constants c1, c2, and c3 such that w1 = c1*v1 + c2*v2 + c3*v3? If you get a solution for the constants, w1 is in Span({v1, v2, v3, w1}), and so cannot be independent of them. If you don't get a solution, w1 isn't in Span({v1, v2, v3, w1}), and so must be independent of them.
  2. Does w2 belong to the span of v1, v2, and v3? Same as above.
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
6
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K