Rudin 2.41, why does an unbounded infinite set have no limit points?

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Discussion Overview

The discussion revolves around the interpretation of a statement from Rudin's text regarding unbounded infinite sets and their limit points, specifically in the context of a sequence in ℝk. Participants explore the implications of the definition of limit points and the nature of the set S constructed from the sequence.

Discussion Character

  • Debate/contested
  • Conceptual clarification

Main Points Raised

  • One participant questions Rudin's assertion that the set S, consisting of points xn with |xn|>n, has no limit points, arguing that certain neighborhoods contain points from S, suggesting the existence of limit points.
  • Another participant counters that the sequence defined by xn is countable and that if there were a limit point, it would imply the existence of a convergent subsequence, which contradicts the unbounded nature of the sequence.
  • A clarification is made that Rudin's definition of S refers to distinct points in an infinite sequence, which are not densely packed, thus lacking a limit point.
  • A later reply indicates that understanding the notation of x_n as a sequence helps resolve the confusion regarding limit points.

Areas of Agreement / Disagreement

Participants express disagreement regarding the existence of limit points for the set S. Some argue that limit points exist based on their interpretations, while others maintain that the nature of the sequence precludes such points.

Contextual Notes

The discussion highlights the importance of definitions and the distinction between sequences and general sets, as well as the implications of boundedness on limit points. There is an acknowledgment of the need for clarity in understanding the properties of sequences in mathematical contexts.

EdMel
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Please let me know if this should be in the Homework section.

Part of Rudin 2.41 says that for a set E in ℝk... "If E is not bounded, then E contains points xn with |xn|>n (n = 1, 2, 3,...)." I can understand the argument this far. I do not get the next sentence "The set S consisting of these points xn is infinite and clearly has no limit point in ℝk". I can understand that S is infinite but to me S clearly does have limit points in ℝk. For example, take the real line, n = 1, S to be the set of points greater than 1 and ε>0. Every neighborhood of p = 2 with radius ε would contain a point in S making p a limit point. This contradicts what Rudin states as 'clearly'. What am I missing here?

Thanks,

Ed
 
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It's not true that an unbounded infinite set has no limit points.

But it's not an arbitrary such set. It's a sequence, so a countable set. A finite set has no limit points. So, any finite subset has no limit points and it's going off to infinity. If there were a limit point, that would contradict the fact that each x_n is bigger than n because there would be some subsequence that converges. A convergent sequence is bounded.
 
EdMel said:
For example, take the real line, n = 1, S to be the set of points greater than 1 and ε>0. Every neighborhood of p = 2 with radius ε would contain a point in S making p a limit point. This contradicts what Rudin states as 'clearly'. What am I missing here?

Thanks,

Ed

Pretty much what the previous poster said, but you're missing the point that rudin is not defining S as ALL points greater than some n, but rather each x_n is ONE point greater than n: in other words, an infinite sequence.

Rudin defines this sequence using distinct points, thus while there are an infinite amount, the points are "discrete" objects, if you will. They do not form a connected set, there is distance between each one. Hence, there is no point such that EVERY neighborhood contains a point of the sequence.
 
I get it now. Back in 2.7 he defines a sequence and whenever you see x_n for (n=1, 2, 3,...) you should read this as a sequence.

Thanks.
 

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