Rugby Player Collision Question-- 1. The problem statement, all variables and given/known data Two rugy players are running towards each other. They are 37 m apart. If one is accelerating from rest at 0.5m/s² and the other was already moving at 3.1 m/s and maintains her speed, a) how long before they crunch together? b) how fast was the accelerating player going? c) how far has each player run? 2. Relevant equations In this situation: The five equations of linear kinematics v2 = v1 + a∆t ∆d = ½(v2 + v1)∆t ∆d = v1∆t + ½a∆t² ∆d = v2∆t - ½a∆t² v2² = v1² + 2a∆d 3. The attempt at a solution 37-d= a(d/v)²/2 37-d= a(d²/v²)/2 74-2d= a(d²/v²)...... And I trailed off from there as I was confused. Now I know you may have to isolate the displacement in this case, however I have not yet encountered a question like this before and it was not clearly explained to me beforehand. Hopefully I'll know what to do through these forums.