Runner and a bird heading towards finish line

  • Thread starter Thread starter anglum
  • Start date Start date
  • Tags Tags
    Bird Line
Click For Summary
SUMMARY

The discussion revolves around a mathematical problem involving a runner and a bird, where the runner jogs at 3.4 km/h and the bird flies at 10.2 km/h. The bird travels a total distance of 6.149975 km before the runner reaches the finish line. The participants explore the calculations needed to determine the bird's total distance traveled, including multiple encounters with the runner until he finishes the race. The final answer for the time taken for the runner to reach the finish line is 1.205882353 hours, which can be used to calculate the bird's total distance flown.

PREREQUISITES
  • Understanding of relative velocity concepts
  • Basic algebra for solving equations
  • Knowledge of time-distance-speed relationships
  • Familiarity with unit conversions (e.g., km to m)
NEXT STEPS
  • Calculate the total distance traveled by the bird using the formula: distance = speed × time.
  • Explore the concept of relative motion in physics to understand interactions between moving objects.
  • Learn about geometric series to analyze repeated encounters in similar problems.
  • Study the application of calculus in motion problems for more complex scenarios.
USEFUL FOR

Students in mathematics or physics, educators teaching motion problems, and anyone interested in solving real-world applications of relative speed and distance calculations.

  • #31
so i then get

.0177935943D=.0146627566D + .0019208211

i then get .0031308377D = .0019208211

D = .6135166636 km

that is the D then i solve for t of the equation

t = .6135166636/68.2

t = .008 hours? that doesn't seem right to me
 
Last edited:
Physics news on Phys.org
  • #32
anglum said:
since the cars travel at km/s and the distance between them is 131 m... doesn't that have to be .131 km in the equation to get a true correct answer?

yeah, that's right sorry.
 
  • #33
anglum said:
so i then get

.0177935943D=.0146627566D + .0019208211

i then get .0031308377D = .0019208211

D = .6135166636 km

that is the D then i solve for t of the equation

t = .6135166636/68.2

t = .008 hours? that doesn't seem right to me
i then take .008 hours and convert to minutes which is .5397507304 mins then convert again to seconds by multiplying by 60 which gives me a time in seconds of 32.385

? is that the answer that you got for this problem? because i get that as being wrong when entered on the classroom online

this was the original info

how long does it take car traveling 68.2km/h to become even with a car that is traveling in another lane at 56.2km/h if the front bumpers are initially .131 km apart
 
Last edited:
  • #34
something in my calculations must be wrong or else the methods i used to solve were not correct
 
  • #35
learning have u done this problem and gotten an answer in seconds for the time it would take for them to be even and directly next to each other
 
  • #36
anglum said:
so i then get

.0177935943D=.0146627566D + .0019208211

i then get .0031308377D = .0019208211

D = .6135166636 km

that is the D then i solve for t of the equation

t = .6135166636/68.2

You should divide by 56.2 right? your d looks right...
 
  • #37
why divide by 56.2?

im tryin to see how long it takes for the car goin 68.2km/h to catch up?
 
  • #38
anglum said:
how long does it take car traveling 68.2km/h to become even with a car that is traveling in another lane at 56.2km/h if the front bumpers are initially 131 m apart


i have tried this so far

do i need to convert the 131 m to . 131 km??

d = 56.2km/h * t

and

d +131 = 68.2 km/h * t

Since you're solving for time sub. d from the first equation into the second...

56.2t + 0.131 = 68.2t

solve for t.
 
  • #39
anglum said:
why divide by 56.2?

im tryin to see how long it takes for the car goin 68.2km/h to catch up?

The times are equal... you can also do (d+0.131)/68.2 it's the same time...
 
  • #40
ahhh that makes total sense and now i got the correct answer as 39.3seconds

thanks learning

i am going to post a new thread on one last question if u don't mind
 

Similar threads

  • · Replies 20 ·
Replies
20
Views
3K
Replies
2
Views
2K
  • · Replies 5 ·
Replies
5
Views
5K
Replies
16
Views
6K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 7 ·
Replies
7
Views
4K
Replies
3
Views
4K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
13
Views
3K
  • · Replies 8 ·
Replies
8
Views
4K