Rutherford Scattering and relativistic effects

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SUMMARY

The discussion focuses on calculating the kinetic energy of an alpha particle in a Rutherford scattering experiment, where the de Broglie wavelength equals the target nucleus's diameter of 3.5 x 10-14 m. The relevant equation used is E = hc/λ, where E represents energy, h is Planck's constant, c is the speed of light, and λ is the de Broglie wavelength. The mass of the alpha particle is given as 6.64 x 10-27 kg, and relativistic effects are ignored for this calculation.

PREREQUISITES
  • Understanding of de Broglie wavelength
  • Familiarity with Planck's constant (h)
  • Knowledge of kinetic energy equations
  • Basic principles of Rutherford scattering
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Homework Statement



n a Rutherford scattering experiment a target nucleus has a diameter of 3.5 10-14 m. The incoming has a mass of 6.64 10-27 kg. What is the kinetic energy of an particle that has a de Broglie wavelength equal to the diameter of the target nucleus? Ignore relativistic effects.
J



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Damn dude, here's the equation you need:

E=\frac{hc}{\lambda}
E is the energy, h is the planks constant, c (more properly v) is the speed of the particle, and lambda is the de-broglie wavelength.

E and KE are equal in this case.
 

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