Rutherford's 1911 Experiment: Electric Field & Deflection Formula

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SUMMARY

The forum discussion centers on E. Rutherford's 1911 experiment regarding the scattering of alpha particles and the associated electric field formula. The electric field inside an atom is expressed as X = N e (1/r^2 - r/R^3), where N e represents the electric charge in the nucleus and R is the atomic radius. The deflection angle, theta, is given by the formula theta = b/p (1 - p^2/R^2)^(3/2), with p being the perpendicular distance from the center to the particle's path. Participants discuss methods to derive the theta formula, emphasizing the integration of force components along the particle's trajectory.

PREREQUISITES
  • Understanding of Rutherford's 1911 experiment and its significance in atomic physics.
  • Familiarity with electric field equations and their applications in particle physics.
  • Knowledge of calculus, particularly integration techniques for force analysis.
  • Basic concepts of particle trajectory and deflection in a field.
NEXT STEPS
  • Study the derivation of electric field equations in atomic models, focusing on Rutherford's work.
  • Learn about the integration of force components in particle trajectories, particularly in electric fields.
  • Explore the implications of small-angle approximations in deflection calculations.
  • Investigate the historical context and advancements following Rutherford's experiment in nuclear physics.
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Students and researchers in physics, particularly those focusing on atomic structure, particle dynamics, and historical experiments in nuclear physics.

D.Hilbert
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Hi,

My question is about the famous paper by E. Rutherford on the scattering of alpha particles (1911). The paper is easy to find on internet. Rutherford gives the formula for the electric field inside an atom, at a distance r from the nucleus (here reduced to a point):

X = N e (1/r^2 - r/R^3)

Here N e in the electric charge in the nucleus and R is the radius of the atom. After he says

It is not difficult to show that the deflection (supposed small) of an electrified particle due to this field is given by

theta = b/p (1 - p^2/R^2)^(3/2)

where p is the perpendicular from the center on the path.

I can obtain X but I don't see where the formula for theta comes from.

Any suggestion?

Thanks DH
 
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If I were old Ernest, I would integrate the vertical component of the force over the section of the trajectory through the nucleus. If theta is small enough, pretending it is straight may be OK, and it's easier.
 
Hi,
Thanks for the answer.
Let the trajectory of the alpha particle be on the x-axis.

Are you suggesting to calculate

\int_{t1}^{t2} Fy dt

where Fy is the y-coordinate of the force?

DH
 
I found Rutherford-1911 where your formulas feature. There also is an explanation of what b stands for, which you would have included in your problem statement if you would have used the template. Please use it from now on. PF has a simple rule: no template, no assistance. It would have saved me some time that I could have used for others. Now I have to do some errands, so I am short on time.

But yes, (read: atom in my post, the nucleus is considered pointlike, somewhat incongruent in this context: it still had to be discovered. Better to speak of the center of the atom, but never mind). t1 and t2 can be related to R and p and the speed of the ##\alpha##. So you change from dt to dx. Some ##\beta## comes in with ## \sin\beta = {x\over R}##; perhaps you go from dx to d##\beta##. All constants go into b and there you are!
 
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