S^2 union a line connecting the north and south pole

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SUMMARY

The fundamental group of the space S^2 union a line connecting the north and south pole is confirmed to be isomorphic to the integers, denoted as $\mathbb{Z}$. This conclusion is derived using the Seifert Van Kampen Theorem and the analysis of the universal cover, which is represented as an infinite string of spheres. The group of deck transformations of this covering space is identified as $\mathbb{Z}$, establishing a clear connection between the fundamental group and the covering space's structure.

PREREQUISITES
  • Understanding of the Seifert Van Kampen Theorem
  • Familiarity with fundamental groups in algebraic topology
  • Knowledge of covering spaces and deck transformations
  • Basic concepts of homotopy and homotopic equivalence
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  • Explore the properties of covering spaces and their fundamental groups
  • Learn about homotopy equivalence and its implications in topology
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Mathematicians, particularly those specializing in algebraic topology, students studying topology concepts, and anyone interested in understanding the properties of fundamental groups and covering spaces.

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I have been trying to determine the fundamental group of S^2 union a line connecting the north and south pole by using the Seifert Van Kampen Theorem. But every time I try and pick my two subsets U and V they are either not open or not arcwise connected or their intersection isn't particularly nice.

My guess is that the fundamental group should be $\mathbb{Z}$, but other than my intuition, I can't seem to find a way to show this.
 
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look at the universal cover, an infinite string of spheres like beads on a long string.
 
Thanks! So, I look at the group of deck transformations of the universal covering space (the string of beads), which I believe is Z. Then since the group of deck transformations of the universal covering space is isomorphic to the fundamental group, we are done.
 
Just for concreteness, what is the reason that the universal cover is this string of beads?

If you wanted to use Van Kampen, couldn't you take the "left of the sphere with the string" along with the "right of the sphere with the string"? Each piece will be homotopic to a circle and their overlap will be homotopic to a figure 8. It seems that the amalgamation will identify the two generators and you indeed get the integers, which is the "obvious" answer.
 
Oh, I was thinking of your bead incorrectly, I see why it is the universal cover, never mind!
 
well you are right i ignored the question. but the cover makes it obvious the group is Z. (i think?)
 
No, your answer was nice, much nicer than using Van Kampen- I was just noting that it isn't too hard to use Van Kampen if that's what the OP wanted to do.

I've just thought again about your answer. Do I have this right- in your bead, I imagine your sphere (and interval) being cut in halves along the equator, and then the interval is made to point out in the opposite direction. You then glue these all back together in the obvious way. It will have trivial fundamental group since it is homotopic to a wedge of spheres and the covering map sends a point to where it came from in the above construction.

The set of deck transformations is Z, because it just matters where you send some particular sphere (I was worried about "flipping" everything being a self-homeomorphism- but thinking about it, this won't be a deck transformation).
 

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