Sag in wire due to a weight (given the Young's modulus)

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SUMMARY

The discussion focuses on calculating the sag in a mild steel wire of length 1 m and cross-sectional area 0.5 x 10^-2 cm^2 when a 100 g mass is suspended from its midpoint. The sag formula provided, WL^3/(4BD^3Y), is not applicable to a wire due to its tension-based support rather than bending. Participants emphasize the need for a free body diagram to analyze the forces acting on the weight and suggest treating the wire as a string to simplify calculations. The discussion concludes that understanding tensile stress and geometry is essential for deriving the correct equations for sag.

PREREQUISITES
  • Understanding of Young's modulus and its application in material science.
  • Familiarity with basic statics and free body diagrams.
  • Knowledge of tensile stress and its implications in wire mechanics.
  • Ability to apply geometric principles to solve problems involving deflection and sag.
NEXT STEPS
  • Learn how to draw and interpret free body diagrams in statics problems.
  • Study the relationship between tensile stress and elongation in materials.
  • Explore the concept of catenary curves and their relevance to suspended cables.
  • Investigate the effects of different cross-sectional shapes on wire behavior under load.
USEFUL FOR

Students studying physics, engineers working with materials under tension, and anyone interested in understanding the mechanics of wire suspension systems.

ezioauditore
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Homework Statement


A mild steel wire of length 1 m and cross-sectional area 0.5*10^-2 cm^2 is stretched within elastic limit horizontally between two pillars.A mass of 100 g is suspended from mid-point.Depression at mid-point?

Homework Equations



Sag in metal rod is=WL^3/(4BD^3Y) where W=weight, l=length,b=breadth,d=depth,Y=Young's modulus.But here its a wire.

The Attempt at a Solution


I tried to calculate the k of the wire since its stretched within its elasticity limit and found out the increase in length of the wire.But could not relate the sag to increase in length.
 
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ezioauditore said:

Homework Statement


A mild steel wire of length 1 m and cross-sectional area 0.5*10^-2 cm^2 is stretched within elastic limit horizontally between two pillars.A mass of 100 g is suspended from mid-point.Depression at mid-point?

Homework Equations



Sag in metal rod is=WL^3/(4BD^3Y) where W=weight, l=length,b=breadth,d=depth,Y=Young's modulus.But here its a wire.

The Attempt at a Solution


I tried to calculate the k of the wire since its stretched within its elasticity limit and found out the increase in length of the wire.But could not relate the sag to increase in length.
Your sag formula for the metal rod appears to be developed for a rod with a rectangular or square cross section, which is not the cross section of a typical steel wire.
The wire is not going to be in bending; it supports the load by remaining in tension.

You should analyze this problem from first principles by drawing a free body diagram showing the weight suspended between two supporting points. Without getting into catenaries and stuff, you can assume each part of the wire suspending the weight is straight. You want the tensile stress in each part of the wire to be less than the elastic limit, whatever that number is.
 
Show your attempt with all your working.
I think it's fair to assume the wire has zero stiffness, treat it as a string not a beam (or rod).
Draw a free body diagram of the weight and show how tension varies with angle (note how tension goes to infinity as theta goes to zero). Extension/sag depends on tension and tension depends on sag...
 
+1

I would make TWO drawings..

1) A free body diagram showing the forces acting on the weight. This should lead you to equations - hint it's a statics problem.
2) A diagram showing the wire straight and deflected by the weight. Some geometry will give you an equation for the change in length of the wire(s).

Eventually you will have enough equations to solve it all.
 

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