1. The problem statement, all variables and given/known data Three separate members of steel, copper and brass are of identical dimensions and are equally loaded axially.Young’s moduli for the materials are: steel, 210,000 N/mm^2 copper, 100,000 N/mm^2 brass, 95,000 N/mm^2 If the steel member stretches 0.13mm, calculate the amount of elongation in the copper and brass members. 2. Relevant equations The equation i believe to be relevant; Young's modulus=Stress/Strain 3. The attempt at a solution I am confused how to approach this question at first i believed i had to find the stress by using the elongation of 0.13mm, and because all the members would be under the same stress i could then input that information into a youngs modulus equation for the other two members. However the young's modulus equation requires strain not just the elongation and i don't know the original length. The only way I can think of solving this question would to assume that the strain = 0.13 and solve the question like so Steel young's modulus= stress/strain 210=stress/0.13 stress=210*0.13=27.3 Starting with brass as an example Young's modulus = stress/strain strain= stress/young modulus Strain= 27.3/95 =0.29 mm and Copper =0.27mm Is this assumption correct, if not any hints on how i could go about solving this problem? Thank you very much.