(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A sailboat is traveling east at 5.1m/s . A sudden gust of wind gives the boat an acceleration = (0.80 m/s^{2}}, 40° north of east).

What is the boat's direction 6s later when the gust subsides?

2. Relevant equations

V_{f}= V_{0}+ at

3. The attempt at a solution

To solve I simply created X and Y components of the velocity after those six seconds, in order to use the arctan function to then find my angle:

V_{fx}= V_{ox}+at

V_{fx}= 5.1 m/s + (6s)* (0.80cos40) = 8.777013327 m/s (x)

V_{fy}= 0 m/s +(6s) * (0.80sin40) = 3.085380526 m/s (y)

To find the angle, I then simply input these values into the arctan function:

tan^{-1}(vy/vx) = θ

tan^{-1}(3.085/8.777) = 19°, north of east

This answer, however, is incorrect. Do you have any advice on my approach, or anything that I may be negating my calculations?

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# Homework Help: Sailboat Direction - Kinematics in Two Directions

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