A sailboat is traveling east at 5.1m/s . A sudden gust of wind gives the boat an acceleration = (0.80 m/s2}, 40° north of east).
What is the boat's direction 6s later when the gust subsides?
Vf = V0 + at
The Attempt at a Solution
To solve I simply created X and Y components of the velocity after those six seconds, in order to use the arctan function to then find my angle:
Vfx = Vox+at
Vfx = 5.1 m/s + (6s)* (0.80cos40) = 8.777013327 m/s (x)
Vfy = 0 m/s +(6s) * (0.80sin40) = 3.085380526 m/s (y)
To find the angle, I then simply input these values into the arctan function:
tan-1(vy/vx) = θ
tan-1(3.085/8.777) = 19°, north of east
This answer, however, is incorrect. Do you have any advice on my approach, or anything that I may be negating my calculations?