Graduate Sampling Electrons from a 2D Projection: Is There a Functional Form?

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SUMMARY

The discussion centers on sampling electrons from a 2D projection derived from a 3D Gaussian source within a uniform electric field. The resulting image displays a higher concentration of electrons at the edges, prompting the need for a functional form to represent this 2D distribution. The user suggests that the distribution may resemble a spherical projection, proposing the use of a sine function to calculate the percentage of electrons in concentric rings. Specifically, the formula for the percentage of dots in a ring is defined as sin(πr/2R), where R is the radius of the circle and r is the radius of the ring.

PREREQUISITES
  • Understanding of 3D Gaussian distributions
  • Familiarity with electric field dynamics
  • Knowledge of spherical coordinates and projections
  • Basic trigonometric functions, particularly sine
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  • Research "3D Gaussian distribution in electric fields"
  • Explore "spherical coordinates and their applications"
  • Study "trigonometric functions in physics simulations"
  • Investigate "Monte Carlo methods for particle sampling"
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Physicists, simulation engineers, and researchers working on particle detection and distribution modeling in electric fields.

Malamala
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Hello! I have some electrons produced from a 3D gaussian source isotropically inside a uniform electric field. The electric field guides them towards a position sensitive detector and I end up with an image like the one below (with more electrons on the edge and fewer as you move towards the center). I want to run some simulations and for that I need to sample electrons from this 2D projection. Is there a functional form for this 2D distribution? Can someone point me towards some reading/Wikipedia page? Thank you!

electrons.png
 
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I don't know the distribution but the picture reminds me of the recent universe map that used logarithmic distances.

Also it looks like a sphere so that maybe you could assume equally spaced dots on a sphere projected onto a plane that slices the sphere in half.

Lastly, you might be able to construct the distribution using the value of a sin() function as the percentage of dots in a given ring around the center.

R = radius of your circle
r = radius of a ring

r/R = ranges from 0 to 1

##\frac{\pi}{2} \times \frac{r}{R}## = ranges from 0 to ##\pi/2##

percentage of dots in a ring = ##sin(\frac{\pi r}{2 R})##

or something like that -- your call.
 
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