Sandbag dropped from balloon - find final velocity

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SUMMARY

The discussion focuses on calculating the horizontal displacement of a hot-air balloon and the final velocity of a sandbag dropped from it. Given a constant horizontal wind speed of 1.10 m/s and a vertical ascent speed of 2.50 m/s, the balloon reaches a height of 205 m before releasing the sandbag. The horizontal displacement of the balloon is determined to be 190 m, while the sandbag lands 180 m from the launch site. The time taken for the balloon to reach 205 m is calculated as 82 seconds, and the final velocity of the sandbag upon impact is 6.018 m/s.

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Chupu
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1. Experiencing a constant horizontal 1.10 m/s wind, a hot-air balloon ascends from the launch site at a constant vertical speed of 2.50 m/s. At a height of 205 m, the balloonist maintains constant altitude for 10.0 s before releasing a small sandbag. What is the horizontal displacement of the balloon? How far from the launch site does the sandbag land? How long it takes the balloon to reach the 205 m? What is the final velocity of the of the sandbag?

Thank you guys :)
 
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My guesses are the

horizontal displacement: 190m
how far from launch site: 180m
the balloon took: 82s
the final velocity: 6.018m/s
 


Why guess? All of these things are exactly knowable. What equations did you use for each result?
 

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