Satellite orbiting the Earth (heat radiation)

AI Thread Summary
The discussion focuses on calculating the mass of a satellite, which is determined to be approximately 750g using the formula for volume and density. Participants express uncertainty about integrating the heat transfer equation, specifically regarding the temperature variable T and the function to integrate. The integration process for heat transfer, represented as dQ = eσAT^4dt, is discussed, with attempts to clarify the limits of integration. Questions arise about the meaning of E in the equation E = mcΔT and its relationship to the satellite's heat radiation. Overall, the conversation revolves around the complexities of heat radiation calculations for a satellite in orbit.
glorfindel1000
Messages
1
Reaction score
2
Homework Statement
Satellite is orbiting earth and is heated by sun to 323 K. To what temperature satellite cools down during its 45 min cycle in shadow? Satellite is 1 m radius and 2 mm thick copper. Emissivity is 0,75. Space temperature is assumed to be 0 K.(hint. Write a formula to heat change in function of time, you have to integrate)
Relevant Equations
\begin{align*}
\frac{dQ}{dt} &= e \sigma A T^4 \text{ or } \frac{dQ}{dt} = e * \sigma * A * T^4 \\
\text{(maybe)}E &= cm \Delta T \\
A &= 4 * \pi * r^2 \\
\sigma &= 5,67 \times 10^{-8}{\rm W/(m^2 * K^4)} \\
e &= 0,75
\end{align*}
Mass of a satellite is 750g(##m = \rho V = 8,96 \frac{g}{cm^3}\cdot (\frac{4\pi(100cm)^3}{3} -\frac{4\pi(99,9cm)^3}{3}) = \approx 750g =0,75kg##)

I am not sure what to integrate. I solved T there but it seems far stretched
$$T =\sqrt[4]{\frac{dQ}{dt}\frac{1}{e\sigma A}} $$

How to get the function to integrate is basically my problem. I changed that dt to other side

##dQ = e\sigma AT^4dt##

and integrated it from 0 to 2700.

##Q = \bigg/_{\!\!\! 0}^{\,2700}e\sigma AT^4t##

Not really sure if that helps. What to do with Q then?
 
Last edited by a moderator:
Physics news on Phys.org
Use two # characters like # # (minus the space) to delimit an inline latex statement. Use $ $ to delimit a separate block. Below the bottom left of the window you are typing in, there is a link for more latex help. I edited your post to fix latex. Please make sure I did not cause more problems.
 
I fixed the LaTeX in the relevant equations section as well. Separate equations were running together, which made them confusing to understand.

In your second relevant equation, ##E = mc\Delta T##, what does the ##E## stand for? How is it related to the heat radiated away by the satellite?
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
Thread 'Trying to understand the logic behind adding vectors with an angle between them'
My initial calculation was to subtract V1 from V2 to show that from the perspective of the second aircraft the first one is -300km/h. So i checked with ChatGPT and it said I cant just subtract them because I have an angle between them. So I dont understand the reasoning of it. Like why should a velocity be dependent on an angle? I was thinking about how it would look like if the planes where parallel to each other, and then how it look like if one is turning away and I dont see it. Since...
Thread 'Correct statement about a reservoir with an outlet pipe'
The answer to this question is statements (ii) and (iv) are correct. (i) This is FALSE because the speed of water in the tap is greater than speed at the water surface (ii) I don't even understand this statement. What does the "seal" part have to do with water flowing out? Won't the water still flow out through the tap until the tank is empty whether the reservoir is sealed or not? (iii) In my opinion, this statement would be correct. Increasing the gravitational potential energy of the...
Back
Top