- #1
glorfindel1000
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- Homework Statement
- Satellite is orbiting earth and is heated by sun to 323 K. To what temperature satellite cools down during its 45 min cycle in shadow? Satellite is 1 m radius and 2 mm thick copper. Emissivity is 0,75. Space temperature is assumed to be 0 K.(hint. Write a formula to heat change in function of time, you have to integrate)
- Relevant Equations
- \begin{align*}
\frac{dQ}{dt} &= e \sigma A T^4 \text{ or } \frac{dQ}{dt} = e * \sigma * A * T^4 \\
\text{(maybe)}E &= cm \Delta T \\
A &= 4 * \pi * r^2 \\
\sigma &= 5,67 \times 10^{-8}{\rm W/(m^2 * K^4)} \\
e &= 0,75
\end{align*}
Mass of a satellite is 750g(##m = \rho V = 8,96 \frac{g}{cm^3}\cdot (\frac{4\pi(100cm)^3}{3} -\frac{4\pi(99,9cm)^3}{3}) = \approx 750g =0,75kg##)
I am not sure what to integrate. I solved T there but it seems far stretched
$$T =\sqrt[4]{\frac{dQ}{dt}\frac{1}{e\sigma A}} $$
How to get the function to integrate is basically my problem. I changed that dt to other side
##dQ = e\sigma AT^4dt##
and integrated it from 0 to 2700.
##Q = \bigg/_{\!\!\! 0}^{\,2700}e\sigma AT^4t##
Not really sure if that helps. What to do with Q then?
I am not sure what to integrate. I solved T there but it seems far stretched
$$T =\sqrt[4]{\frac{dQ}{dt}\frac{1}{e\sigma A}} $$
How to get the function to integrate is basically my problem. I changed that dt to other side
##dQ = e\sigma AT^4dt##
and integrated it from 0 to 2700.
##Q = \bigg/_{\!\!\! 0}^{\,2700}e\sigma AT^4t##
Not really sure if that helps. What to do with Q then?
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