Save Tarzan and Make sure his Vine doesnt break(HELP NEEDED)

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SUMMARY

The discussion centers on calculating the maximum force exerted on a vine when Tarzan swings from a cliff. Tarzan weighs 634 N and swings from a 13 m vine, descending 1.4 m. The vine will break if the force exceeds 1220 N. The maximum force on the vine occurs at the lowest point of the swing, where the tension in the vine must counteract both the centripetal force and the gravitational force acting on Tarzan.

PREREQUISITES
  • Understanding of centripetal force and acceleration
  • Knowledge of gravitational force calculations
  • Familiarity with Newton's laws of motion
  • Basic principles of circular motion
NEXT STEPS
  • Calculate the centripetal acceleration using the formula F_{cent}=\frac{mv^2}{R}
  • Determine the velocity of Tarzan at the lowest point of the swing
  • Analyze the forces acting on Tarzan at the bottom of the swing
  • Explore the implications of tension in ropes and breaking points in physics
USEFUL FOR

Physics students, educators, and anyone interested in mechanics, particularly in analyzing forces in circular motion scenarios.

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Tarzan, who weighs 634 N, swings from a cliff at the end of a convenient vine that is 13 m long . From the top of the cliff to the bottom of the swing, he descends by 1.4 m. The vine will break if the force on it exceeds 1220 N. What would the greatest force on the vine be during the swing?

What is the proper stategy for solving this. Such as, "do i need to find a force first or a velocity or an angle" etc. I am not sure how to go about doing this .
 
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When Tarzan jumps, he will swing along a circular arc.
The centripetal acceleration is supplied by the tension in the vine.
F_{cent}=\frac{mv^2}{R}
So it is greatest when Tarzan has the greatest speed. When is that?
 
The rope must also overcome the force of gravity acting on Tarzan when he is at the bottom of the arc.

Thusly, the tension of the rope = Fcent + Fgrav at this point.
 

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