The discussion centers on the scaling factor of energy in a capacitor when charge changes, specifically referencing AQA Section A Q18 from June 2011. The key equations involved are E = 0.5QV and C = Q/V. It is established that if the charge (Q) increases by 1.5 times while capacitance (C) remains constant, the voltage (V) must also increase by 1.5 times, resulting in the energy (E) increasing by a factor of 2.25. The logic and method applied in the solution are confirmed as correct by participants in the discussion.
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mrcotton said:Homework Statement
AQA Section A Q18 Jun 11
Homework Equations
The answer should be C
E=.5QV and C=Q/V
The Attempt at a Solution
So the original Q has increased by 1.5 times If C is constant than the voltage must also increase by 1.5 times
Now the energy E is E=.5QV V has increase by 1.5 and and so has Q which is 2.25
Infact in typing this out I think I just solved it. Is this logic and method ok