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Homework Help: Scaling factor of Energy in a capacitor with change in charge

  1. Jan 9, 2013 #1
    1. The problem statement, all variables and given/known data
    AQA Section A Q18 Jun 11

    2. Relevant equations

    The answer should be C

    E=.5QV and C=Q/V
    3. The attempt at a solution

    So the original Q has increased by 1.5 times If C is constant than the voltage must also increase by 1.5 times

    Now the energy E is E=.5QV V has increase by 1.5 and and so has Q which is 2.25

    Infact in typing this out I think I just solved it. Is this logic and method ok
  2. jcsd
  3. Jan 9, 2013 #2


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    Homework Helper

    Seems fine to me.
  4. Jan 10, 2013 #3
    Yup. You may recall that the energy stored in a capacitor is also given by:

    [itex] E = \frac{1}{2}CV^2[/itex]
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