Scattering and wavelength dependence

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    Scattering Wavelength
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SUMMARY

The discussion centers on the relationship between scattering and wavelength dependence in optics. It is established that shorter wavelengths, such as blue light, are scattered more efficiently than longer wavelengths like red light, which is why the sky appears blue. The scattering efficiency for atmospheric particles smaller than the wavelength follows the formula 1/(wavelength)^4, while for spheres of arbitrary size, Mie scattering applies, with efficiency proportional to 1/x^2, where x is the radius to wavelength ratio.

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  • Understanding of basic optics principles
  • Familiarity with scattering theories
  • Knowledge of Mie scattering and Rayleigh scattering
  • Concept of wavelength and its relation to energy
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  • Research Rayleigh scattering and its mathematical formulation
  • Explore Mie scattering and its applications in atmospheric science
  • Study the impact of wavelength on light scattering in different mediums
  • Investigate the role of particle size in scattering phenomena
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coke
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i don't know why the longer the wavelength, the easier for it to be sattered ?
 
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Welcome to PF, Coke.
I have pretty much zero knowledge of optics, but I would suspect that it's simply because longer wavelengths are less energetic. Red light, therefore, would be more likely to be 'diluted' than blue.
There are quite a few guys here who know an awful lot more about the subject, and they'll be with you shortly.
 
It's not always true that longer wavelengths are scattered more. In fact, the sky appears blue because shorter wavelengths are scattered more efficiently in the atmosphere.

In any case, the question can be simply "How does scattering depend on wavelength"? And the answer to that would fill several books. For atmospheric scattering (particles that are much smaller than a wavelength), the scattering efficiency goes as 1/(wavelength)^4. For spheres of arbitrary size, the scattering goes as 1/x^2, where x = radius/wavelength (Mie scattering).
 

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