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Schwarzschild and Newton potential

  1. Jun 22, 2010 #1
    Expressing the Schwarzschild in the Weyl form allows one to use the Newton potential. The Newton potential here is, perhaps surprisingly, equivalent with a rod of length 2M and mass M. Also the rod is exactly positioned where r = 2M. Furthermore if we decrease the length of the rod to the solution of a point mass, the solution is no longer spherically symmetric.

    What, if anything, do you think is the significance of all this?

    Fair question: Does the Schwarzschild solution refer to a removed rod or to a removed point mass?
     
    Last edited: Jun 22, 2010
  2. jcsd
  3. Jun 23, 2010 #2
    Wait a minute, what do you mean by "Weyl form" here? And then how was the above image of the Newtonian potential in this "form" given?

    AB
     
  4. Jun 24, 2010 #3

    Mentz114

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    Gold Member

    Do you have a reference I can look at ? One way of putting a Schwarzschild black hole into a Weyl vacuum is discussed in this paper, arXiv:gr-qc/0502062v1, but their [itex]\psi[/itex] ( equation 8) doesn't look like a Newtonian potential.
     
    Last edited: Jun 24, 2010
  5. Sep 16, 2011 #4
  6. Sep 17, 2011 #5

    Bill_K

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    This is a well-known result, but no, I don't think there's any significance to it.
     
  7. Sep 17, 2011 #6
    The significance, if any is that since nothing can be physically a rod and a point at the same time that would make r=2m a physical singularity. So I would take Bill's advice and ignore it.
     
  8. Sep 17, 2011 #7
    Ignoring things that can both be interesting and educational?

    Looks like this forum is going downhill.
     
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