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Seat belt forces on car

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  1. Oct 12, 2012 #1
    Hi all,

    I'm having an online discussion and curious to know about the forces a 3-point seat belt has on a car.

    One guy is fitting this retractable belt to his car.

    P1000672.jpg

    The retractor and anchor mount at one bolt hole, the anchor is off centre, it attaches via a steel extension piece, the section of extension piece you can't see is behind the retractor and bolted to the same hole the retractor is.

    His car has two 'factory installed' lower mounting holes on one side, a separate hole each for the retractor and anchor and I advised him to mount the belt as it is here.

    asa%20seat%20belt%20load%20chart%20-%20colored%20wording_thumb.jpg

    Saying 'Personally I'd use the factory bolt hole, in an accident you have the force distributed between four anchor points not three'

    I received a reply from someone saying

    the force isn't divided up between four anchor points, it's really only three, the two floor ones on the side of the car and the one on the trans tunnel side.
    The tunnel side gets 50% and the side ones 25% each


    The top mount at the D-ring definitely experiences force so let's say you remove it.

    Wouldn't the bottom anchor bolts feel an increase in force? When the person in the car experiences a sudden stop, doesn't the resultant force that the car experiences from the seat belt remain the same in both lap belt and lap-sash belt applications?

    My opponent says adding an extra bolt will not distribute the forces evenly but I think he is assuming the tension T will be the same in both seat belt applications.

    s
     
    Last edited: Oct 12, 2012
  2. jcsd
  3. Oct 13, 2012 #2

    mfb

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    Staff: Mentor

    To calculate tension in the belt, consider the required extension when the person moves a distance l: In the conventional setup, this is about 4l. Therefore, tension in the belt (integrated over the belt cross-section) is 1/4 of its stopping force F.
    This is true for all belts which cross the body twice in some way.

    To calculate forces on the anchors, simply count the number of belt parts connected to them: The outer anchor (same side as retractor) and the retractor will get F/4, the inner anchor and the D-ring get F/2.
     
  4. Oct 13, 2012 #3
    do it by parts mate, that should help
     
  5. Oct 13, 2012 #4
    Sorry but what do you mean by extension? The person in restraint has travelled distance L, does the belt stretch by 4 times the travel distance?

    How did you work it out to be 1/4?

    Is it because the person is held back at 4 points (shoulder, belt shoulder side hip, upper right hip, lower right hip) and at each point the force F= m/4 x a

    Yes, Tension T = F/A (Cross sectional area)

    So the force in a lap belt (2-point belt) is twice at F = m/2 x a?

    Or is there an elongation component to the equation and is the elongation more due to the restraining mass at only 2 points?

    Wouldn't the force at the D-ring be 2FCos θ/2 ?

    s
     
  6. Oct 13, 2012 #5

    mfb

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    Approximately. Depends on the precise geometry of the system.
    Inverse of the factor 4.
    Like that, yes.
    If the belt just goes from one side to the other: Yes.
    Ah, you are right. But the angle is small, so I don't expect a big difference.
     
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