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## Homework Statement

Find a third degree polynomial approximation for the general solution to the differential equation:

[tex]\frac{d^{2}y}{dt^{2}}[/tex] +3[tex]\frac{dy}{dt}[/tex]+2y= ln(t+1)

## Homework Equations

Power series expansion for ln(t+1)

## The Attempt at a Solution

The system to the corresponding homogeneous equation [tex]\frac{d^{2}y}{dt^{2}}[/tex] +3[tex]\frac{dy}{dt}[/tex]+2y = 0

is y(t) = k

_{1}e

^{-t}+k

_{2}e

^{-2t}

Then I guessed[tex]\frac{ at^{3}}{3}[/tex]-[tex]\frac{bt^{2}}{2}[/tex]+ct as a solution for the original equation. Plugging this in I got a=1/2, b=2,c=2/3

But then I still have the t[tex]^{4}[/tex], t[tex]^{5}[/tex] terms, etc left in the equation. Im not quite sure how a third degree polynomial can be a solution to this equation.