(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Find a third degree polynomial approximation for the general solution to the differential equation:

[tex]\frac{d^{2}y}{dt^{2}}[/tex] +3[tex]\frac{dy}{dt}[/tex]+2y= ln(t+1)

2. Relevant equations

Power series expansion for ln(t+1)

3. The attempt at a solution

The system to the corresponding homogeneous equation [tex]\frac{d^{2}y}{dt^{2}}[/tex] +3[tex]\frac{dy}{dt}[/tex]+2y = 0

is y(t) = k_{1}e^{-t}+k_{2}e^{-2t}

Then I guessed[tex]\frac{ at^{3}}{3}[/tex]-[tex]\frac{bt^{2}}{2}[/tex]+ct as a solution for the original equation. Plugging this in I got a=1/2, b=2,c=2/3

But then I still have the t[tex]^{4}[/tex], t[tex]^{5}[/tex] terms, etc left in the equation. Im not quite sure how a third degree polynomial can be a solution to this equation.

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# Homework Help: Second order linear system and power series: Differential Equations

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