Find the solution to :y''+2y'+y=t
And I believe, Y(t)=Yh+Yp. That is the solution is equal to the solution to the homogenous equation, plus the particular solution.
The Attempt at a Solution
First Solve the homogeneous equation:
Substitute this back into the homogenous problem(y''+2y'+y=0) gives:
Solution is t=-2 or B1,B2,B3=0
Now I'm unsure of what to do?
As for the particular solution say Yp:
Yp=ct, where c is a constant so,
Substitute this into :y''+2y'+y=t
Thanks for any help.