Undergrad Second Order ODE with Exponential Coefficients

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SUMMARY

The discussion centers on solving the second order ordinary differential equation (ODE) given by p''(x) - D(e^{\gamma x}/(A - Ae^{\gamma x}))p'(x) - Fp(x) = 0, where D is a nonzero imaginary number and γ, A, and F are nonzero real numbers. The transformation t = e^{\gamma x} simplifies the equation to a form suitable for analysis using Frobenius' method. Participants agree that this approach is appropriate for finding a series solution to the ODE.

PREREQUISITES
  • Understanding of second order ordinary differential equations (ODEs)
  • Familiarity with Frobenius' method for solving differential equations
  • Knowledge of complex numbers, particularly imaginary numbers
  • Basic skills in mathematical transformations and substitutions
NEXT STEPS
  • Study the application of Frobenius' method in solving differential equations
  • Explore the properties of complex numbers in differential equations
  • Research techniques for transforming ODEs using substitutions
  • Investigate the implications of exponential coefficients in ODEs
USEFUL FOR

Mathematicians, physicists, and engineering students who are working with differential equations, particularly those involving complex coefficients and seeking advanced solution techniques.

thatboi
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Hi all,
I have another second order ODE that I need help with simplifying/solving:
##p''(x) - D\frac{e^{\gamma x}}{A-Ae^{\gamma x}}p'(x) - Fp(x) = 0##
where ##\gamma,A,F## can all be assumed to be nonzero real numbers and ##D## is a purely nonzero imaginary number.
Any help would be appreciated!
 
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Set t = e^{\gamma x}. Then <br /> \gamma^2(1-t)t^2 \frac{d^2p}{dt^2} + \left(\gamma^2(1-t)t - \frac{\gamma D}{A} t^2\right) \frac{dp}{dt} - F(1-t)p = 0. This looks like it should be solvable by Frobenius' method.
 

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