Second Quantization: Creation & Annihilation Operators

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The discussion focuses on the relationship between creation and annihilation operators in second quantization and their analogy to bra and ket vectors in first quantization. The kinetic energy operator is expressed using these operators, highlighting their role in designating matrix elements. The creation operator adds a particle to a specific state, and the expansion of these operators includes terms for multiple-particle states. Participants clarify that while the creation operators can be expressed in terms of outer products, they also encompass states with varying particle numbers. This exploration emphasizes the complexity and utility of these operators in quantum mechanics.
Niles
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Hi all

I am reading about second quantization. The kinetic energy operator T we write as

<br /> \hat T = \sum\limits_{i,j} {\left\langle i \right|T\left| j \right\rangle } \,c_i^\dag c_j^{}.<br />

Now, the creation and annihilation operators really seem to be analogous (in some sense) to the ket and the bra in first quantization, since they tell us which matrix element we are talking about.

What is the reason for this? I understand that we have the new states in Fock space (the occupation number states), but my book never illuminates why the creation and annihilation operators designate the matrix elements just like the outer product in first quantization does.
 
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Hi Niles,

The creation operator c_i^+ adds one particle to the system in the single particle state labeled by i. If |i\rangle denotes the state where the system has one particle in single particle state i, then you know that |i\rangle = c_i^+ |\text{vac} \rangle. This means you can write c^+_i = |i \rangle \langle \text{vac} | + \text{...} where ... consists of states with more than one particle. Thus in the single particle Hilbert space the creation operators and annihilation operators are literally the outer products you are more familiar with. For example, c_i^+ c_j = |i \rangle \langle \text{vac} | \text{vac} \rangle \langle j | + \text{...} = | i \rangle \langle j | + \text{...}.

Does this help at all?
 
Hi Physics_Monkey

Yes, that is a very good explanation. Although I do not quite get what you mean by: "where ... consists of states with more than one particle.". We have |i \rangle \langle \text{vac} |, which is an operator. To this operator we add multiple-particle states (i.e. vectors) - is that allowed?
 
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What I mean is that because because c_i^+ adds one particle to any state, the expansion of c_i^+ in terms of outer products can't stop with | i \rangle \langle \text{vac} |. There must be other terms like |\text{2 particles} \rangle \langle \text{1 particle} |. However, each of these terms contains at least one bra or ket with more than one particle. This is what I mean by ... containing states with more than one particle.
 
Time reversal invariant Hamiltonians must satisfy ##[H,\Theta]=0## where ##\Theta## is time reversal operator. However, in some texts (for example see Many-body Quantum Theory in Condensed Matter Physics an introduction, HENRIK BRUUS and KARSTEN FLENSBERG, Corrected version: 14 January 2016, section 7.1.4) the time reversal invariant condition is introduced as ##H=H^*##. How these two conditions are identical?

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