Secular Equilibrium Mass: Th-232 & Po-212

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SUMMARY

The discussion focuses on calculating the mass of Polonium-212 (Po-212) in secular equilibrium with Thorium-232 (Th-232). Given the half-lives of Po-212 (0.16 seconds) and Th-232 (1.41 x 1010 years), along with their atomic masses (A(r)=211.99 g/mol for Po-212 and A(r)=232.04 g/mol for Th-232), participants are prompted to apply relevant equations to derive the solution. The conversation emphasizes the importance of understanding radioactive decay and equilibrium in nuclear chemistry.

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  • Knowledge of secular equilibrium in nuclear reactions
  • Familiarity with atomic mass units and molar mass calculations
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This discussion is beneficial for students in nuclear chemistry, physicists studying radioactive materials, and anyone interested in understanding the dynamics of isotopic equilibrium in radioactive decay processes.

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Homework Statement


What mass of Po-212 (T1/2=0.16sec) is in secular equilibrium with Th-232(T1/2=1.41 x10^10years)? Using A(r)=232.04g.mol-1 for Th-232 and A(r)=211.99g.mol-1 for Po-212


Homework Equations





The Attempt at a Solution


 
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mpoesr said:
What mass of Po-212 (T1/2=0.16sec) is in secular equilibrium with Th-232(T1/2=1.41 x10^10years)? Using A(r)=232.04g.mol-1 for Th-232 and A(r)=211.99g.mol-1 for Po-212

Hi mpoesr ! Welcome to PF! :smile:

Show us what equations you've tried, and where you're stuck, and then we'll know how to help! :smile:
 

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