Semi-empirical mass formula: most stable isobar for odd A

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SUMMARY

The discussion focuses on the application of the Semi-empirical Mass Formula to determine the most stable isobar for odd atomic mass number A. The key equation used is B(A,Z) = aV A − aS A2/3 − aCZ2A-1/3 − aA(Z − N)2/A, where the derivative dB/dZ = 0 is computed to find the maximum binding energy. A critical point raised is the need to account for the factor of one-half in the calculations, which arises from the treatment of the neutron to proton ratio N/Z. The error identified involves incorrectly treating N as constant during differentiation.

PREREQUISITES
  • Understanding of the Semi-empirical Mass Formula
  • Knowledge of binding energy calculations in nuclear physics
  • Familiarity with differentiation techniques in calculus
  • Concept of neutron to proton ratio in nuclear stability
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  • Study the derivation of the Semi-empirical Mass Formula in detail
  • Learn about the significance of pairing terms in nuclear stability
  • Explore the implications of neutron to proton ratios on nuclear binding energy
  • Investigate common errors in calculus related to variable differentiation
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This discussion is beneficial for physics students, nuclear physicists, and researchers focusing on nuclear stability and binding energy calculations.

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Homework Statement


Using the Semi-empirical Mass Formula show that for fixed odd atomic mass
number, A, the most stable isobar has a neutron to proton ratio given by
N/Z = 1 + aCA2/3/(2aA)

Homework Equations


B(A,Z) = aV A − aS A2/3 − aCZ2A-1/3 − aA(Z − N)2/A + pairing term

The Attempt at a Solution


I computed dB/dZ = 0 because the most stable means the one with the maximum binding energy. I get the formula but missing the factor of a half. The fact A is odd means that we don't have a pairing term.

My question is where does the half come from? What am I doing wrong?
 
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We would need to see your computation of dB/dZ to find your mistake. One thing to keep in mind, you cannot treat N as constant while taking the derivative with respect to Z.
 
Last edited:
I think your asymmetric Energy term is an error in the above mentioned B.E formula ..
replace (Z-N) By (N-Z)
 

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