Semiconductor Diodes: Calculating Rf and Why VD=0

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SUMMARY

The discussion focuses on the calculation of diode resistance (Rf) in semiconductor diodes, specifically addressing the assumption of zero voltage drop (VD=0) for ideal diodes during forward biasing. It clarifies that while an ideal diode is a theoretical construct, practical applications often involve real diodes with a forward voltage drop, such as 0.6 volts in rectifying 30 volts AC. The conversation emphasizes the importance of distinguishing between ideal and real diode behaviors in calculations.

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Ghassan99
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Semiconductor dioedes !

when proving that the ideal diode is short circuit in forward biasing we calculate the diode Resistance Rf which is equal to the diode forward voltage upon it's forward current ...but why we put VD=0 why?
 
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These are two different things.

An ideal diode is one that nobody has invented yet, but we assume we have one just to make the other calculations easier. If you are using a diode to rectify 30 volts AC then a voltage drop of 0.6 volts may be a trivial error which can be ignored.

If we don't want to regard the diode as ideal, then we can measure the forward voltages in the way you described.
 


Thank you :)
 

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