dy/dx = (y^2 - 1)/ (x^2 - 1) with initial condition y(2) = 2
Why is y = 1 and/or y= -1 not solutions?
The Attempt at a Solution
I am actually able to solve this differential equation but when I separate the equation according to x and y:
(y^2 - 1)^-1 dy = (x^2 - 1)^-1 dx
here I am dividing both sides of the equation by (y^2 - 1), which means now I have to exclude y = 1 , -1 and check whether they are solutions
Now how do I show that y =1 and y = -1 are not solutions?