(x + 2y) dy/dx = 1, y(0) = 1
The Attempt at a Solution
Problem is, I can't separate it. This might be a homogenous type? If so, how would I make it into the g(y/x) form.
You can write the equation as dy/dx = 1/(x + 2y), where the right side is a function of x and y. I'm just offering a suggested approach based on your first post. It may or may not work.Okay, so since you said y = ux, I am thinking that this is a homogenous equation...
However, if it is a homogeneous equation, before we can plug in y = ux, aren't we suppose to first have the equation in the form of dy/dx = f(x,y), where there exists a function such that f(x,y) is expressed g(y/x).
Then, AFTEr we can do the y=ux thing. correct me if Im wrong.