High School Separation of variables - rocket equation

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The discussion focuses on the derivation of Tsiolkovsky's rocket equation using separation of variables. The user seeks clarification on isolating variables and the integration process involved. Key points include integrating both sides of the equation between the same limits and making a change of variables from velocity to mass. It is emphasized that the integration boundaries should be from the final velocity to the initial velocity, and the integrand remains constant in this case. The conversation highlights the importance of correctly applying integration techniques to understand the derivation better.
Januz Johansen
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hello there
Im trying to do a derivation of tsiolkovsky's rocket equation, but i got stuck at the step when i have to use separation of variables (marked with red in the pic), i used maple to solve it, so i could get on with it, but i want to understand what is happening to solve this, so can anyone explain how to solve this step with separation of variables?
Thanks :)
upload_2016-11-27_15-19-15.png
 
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It is exactly what they have done. What step in particular do you have problems with?
 
Orodruin said:
It is exactly what they have done. What step in particular do you have problems with?

ok thanks so i have done some right ;)

im having trouble explaining what is happening, or i think i do.
I can explain the first steps, just isolate the variables on each side of the equation.
But what rules are used/how is this integrated (the bordered step)
Thanks :D
upload_2016-11-27_15-59-54.png
 
You integrate both sides between the same points. It is essentially making an integration and then making a change of variables.
 
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Orodruin said:
You integrate both sides between the same points. It is essentially making an integration and then making a change of variables.
Thanks i see now :D
 
Oh, and the integration boundaries on the LHS should be ##v_f## to ##v_i##. In this particular example it does not matter for the result because the integrand is constant. You then make a change of variables to ##m(v)## and use ##m_f = m(v_f)## and ##m_i = m(v_i)##.
 
Hello
Do you mean like this?
upload_2016-11-27_16-20-29.png

im not 100% sure what you mean with the change of variables
Again thank you for helping
 

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Yes. Consider the integral
$$
\int_{v_f}^{v_i} dv.
$$
Now, you know that ##m## is a function of ##v## so change variables to ##m##. The integral changes to
$$
\int_{m(v_f)}^{m(v_i)} \frac{dv}{dm} dm.
$$
Insert the known differential equation and perform the new integral.
 
so i have it like so:
upload_2016-11-27_16-46-29.png

or do i get -1/u*m(vi)-m(vf)?
thank you for your patience and help
 
  • #10
No, you have the wrong integration boundaries in the first integral. They are what I said in my post.
 

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