Separation of variables to solve Schrodinger equation

In summary, we use symmetry to find a subset of all possible solutions to the Schrodinger equation. These solutions are finite products of functions that depend only on one coordinate.
  • #1
kini.Amith
83
0
How do we know that separable solutions of Schrodinger equation (in 3d) form a complete basis? I understand that the SE is a linear PDE and therefore every linear combination of the separable solutions will also be a solution , but how do we know that the converse, i.e 'every solution can be written as a linear combination of separable solutions', is true? If we can separate out the variables to get ordinary differential equations, can we take it for granted that the solutions we'll get will be complete?
( I guess my question is not limited to the schrodinger equation alone. I have seen this done to laplace equation also in Electrostatics and I got the same doubt)
 
Physics news on Phys.org
  • #2
The answer is, we do not know it. We must be told that there is some symmetry that forces it to be true. For example, if the system is spherically symmetric or rotationally symmetric, then we can separate out the appropriate angle. Or if the system is invariant in time then we can separate out time.
 
  • #3
DEvens said:
The answer is, we do not know it. We must be told that there is some symmetry that forces it to be true. For example, if the system is spherically symmetric or rotationally symmetric, then we can separate out the appropriate angle. Or if the system is invariant in time then we can separate out time.
That doesn't seem right to me. I am not talking about the case where we can eliminate variables using symmetry.
Consider the case of the 3d rectangular potential well. We find the wave function by assuming it to be a product of three separate functions X(x), Y(y) and Z(z) depending on x, y and z respectively. Plugging it into the schrodinger equation gives us three ordinary differential equations that X, Y and Z satisfy. solving these equations, we find the functions X,Y,Z which turn out to be sinusoidal functions wth arguments that contain nx, ny, nz that can take any positive integer value.
Then we write the general wave function as Ψ= ∑X(x)Y(y)Z(z) over all values of nx, ny, nz
This is surely 'a' solution, but how do we know that this is THE GENERAL solution.
 
Last edited:
  • #4
We do not know that this is the general solution. It is not the general solution. There is no necessity that it is even a solution at all.

In your example we were told that it is a "3d potential well." And then you skipped over a bunch of things where the characteristics of this potential well were omitted. Things like, the well is presumably rectangular. Meaning it has very particular symmetry. And symmetry means that certain things about the wave function must be true.

Now, since you omitted the characteristics of the well, what if it was assumed it was spherically symmetric instead? Would splitting the SE into x, y, and z factors make sense then? Probably not. What about r, theta, and phi? Yes it would.

What if it was a general 3d potential well with arbitrary shaped walls. Maybe the particle is stuck inside a lumpy pyramid or a half deflated crumpled soccer ball. Could we separate the variables then? No, we could not.

Symmetry. It is one of the more powerful tools in our toolbox, particularly in quantum mechanics.
 
  • #5
OK. I meant rectangular potential well. Sorry about that.
I agree that you cannot always separate out variables. Sometimes you can. For a rectangular well, we can if we assume the wave function, like i said in the original post, to be product of 3 functions.
I meant that in cases where we CAN separate them, after solving the resulting Ordinary differential eqns , we find the individual functions and multiply the together to get an infinite family of functions. Let us say that we are able to find some linear combination of them that satisfies the boundary conditions.Do you claim that this solutions NEED NOT be the general solution, i.e other solutions may exist to the same problem?
DEvens said:
We do not know that this is the general solution. It is not the general solution. There is no necessity that it is even a solution at all.
This is causing me some confusion, as every textbook I've read has conveniently left this out. Not just QM, but even in Electrodynamics the solutions to laplace equations subject to different boundary conditions have been done in the same way. I will quote a statement from electrodynamics by Griffiths on separation of variables to solve laplace equation:
We look for solutions that are products of functions, each of which depends only on one coordinate... On the face of it, this is an absurd restriction- the overwhelming majority of solutions to Laplace's equation do not have such a form... obviously, we're only going to get a tiny subset of all possible solutions, and it would be a miracle if one of them happened to fit the boundary conditions of our problem... But hang on, because the solutions we do get are very special, and it turns out that by pasting them together, we can construct the general solution.
I don't know what to make of this.
(i'm sorry for writing everything as sentences. I know i could explain better if I could write some equations, but i am just starting to learn LATEX and it will take days for me to write the code)
 
  • #6
DEvens said:
We do not know that this is the general solution. It is not the general solution. There is no necessity that it is even a solution at all.

In your example we were told that it is a "3d potential well." And then you skipped over a bunch of things where the characteristics of this potential well were omitted. Things like, the well is presumably rectangular. Meaning it has very particular symmetry. And symmetry means that certain things about the wave function must be true.

Now, since you omitted the characteristics of the well, what if it was assumed it was spherically symmetric instead? Would splitting the SE into x, y, and z factors make sense then? Probably not.

I think you're confusing two different issues.
  1. Is there a energy eigenstate of the form: [itex]\psi = X(x)Y(y)Z(z)[/itex]?
  2. Can every square-integrable wave function be written in the form: [itex]\sum_{i,j,k} C_{i,j,k} X_i(x) Y_j(y) Z_k(z)[/itex]?
Unless there is rectangular symmetry, the answer to 1. is "no", but the answer to 2. is still "yes".

Completeness is about the second issue, and whether the potential is spherically symmetric doesn't affect the answer to question number 2 (as far as I know).
 
  • Like
Likes kini.Amith and vanhees71
  • #7
<<Moderator note: Reply to deleted post removed.>>

stevendaryl said:
I think you're confusing two different issues.
  1. Is there a energy eigenstate of the form: ψ=X(x)Y(y)Z(z)\psi = X(x)Y(y)Z(z)?
  2. Can every square-integrable wave function be written in the form: ∑i,j,kCi,j,kXi(x)Yj(y)Zk(z)\sum_{i,j,k} C_{i,j,k} X_i(x) Y_j(y) Z_k(z)?
Unless there is rectangular symmetry, the answer to 1. is "no", but the answer to 2. is still "yes".

Completeness is about the second issue, and whether the potential is spherically symmetric doesn't affect the answer to question number 2 (as far as I know).
Thank you for taking the time to understand my question. The question 2 that you posted was exactly my point.
 
Last edited by a moderator:
  • #8
The completeness of the solutions goes back to the Sturm-Liouville theorem, which states that a Sturm-Liouville operator (with appropriate boundary conditions) has a complete set of eigenfunctions. The reasoning goes something like this (assuming your operator is minus Laplace):

1. Expand the Laplace operator in your coordinates.
2. If in one of the coordinates you have a SL operator, expand the solution in its eigenfunctions. The coefficients of this expansion will generally be functions of the remaining coordinates.
3. Insert your expansion in the original PDE.
4. Repeat step 2 and 3 until you have separated everything and have a solution on the form of a series expansion containing products of functions of the individual coordinates.

Now, it is not certain that this will work out in any coordinate system. The assumption is essentially that your differential operator is separable in your chosen coordinates, the boundaries of your domain are coordinate surfaces, and that the separation gives you SL operators. For example, the Laplace operator does not allow separation in an arbitrary coordinate system.
 
  • Like
Likes kini.Amith, vanhees71 and dextercioby

1. What is the Schrodinger equation?

The Schrodinger equation is a fundamental equation in quantum mechanics that describes how the wave function of a quantum system evolves over time. It is used to calculate the probability of finding a particle in a certain location at a certain time.

2. What is separation of variables?

Separation of variables is a mathematical technique used to solve partial differential equations, such as the Schrodinger equation. It involves breaking down a complex equation into simpler equations that can be solved individually.

3. How is separation of variables used to solve the Schrodinger equation?

In solving the Schrodinger equation, separation of variables is used to separate the time-dependent part of the equation from the spatial part. This allows us to solve for the wave function in terms of time and space separately.

4. What are the advantages of using separation of variables to solve the Schrodinger equation?

Separation of variables is a powerful technique that allows us to solve complex equations by breaking them down into smaller, more manageable parts. It also allows us to apply different methods to solve each separated equation, making the overall solution easier to obtain.

5. Are there any limitations to using separation of variables to solve the Schrodinger equation?

While separation of variables is a useful method for solving the Schrodinger equation, it is not always applicable. It relies on the equation being separable, which is not always the case. In these instances, other techniques must be used to solve the equation.

Similar threads

  • Quantum Physics
Replies
3
Views
1K
Replies
2
Views
2K
Replies
9
Views
2K
  • Quantum Physics
Replies
8
Views
1K
  • Quantum Physics
Replies
19
Views
1K
  • Quantum Physics
Replies
13
Views
3K
Replies
12
Views
2K
Replies
4
Views
4K
Replies
2
Views
639
  • Quantum Physics
Replies
5
Views
1K
Back
Top